Python3-正则表达式-部分替换

1、局部替换

re.sub+lambda

• 注意：不能用$

import re
aa = '【菊部】替换，【a】和【1】不替换'
a = re.sub('【([\u4e00-\u9fa5]+)】', lambda x: x.group(1), aa)

替换前：【菊部】替换，【a】和【1】不替换
替换后：菊部替换，【a】和【1】不替换

import re
aa = '简直，，，，无语。。。。极了！！！'
a = re.sub('[，。！]+', lambda x: x[0][0], aa)
print(a)

打印结果

简直，无语。极了！

headers = '''
GET /Yellow_python HTTP/1.1
Connection: keep-alive
Accept-Encoding: gzip, deflate, br
Accept-Language: zh-CN,zh;q=0.9
'''
d = re.sub('(.+?): (.+)',
           lambda x: "'{}': '{}',".format(x.group(1), x.group(2)),
           headers)
print(d)

打印结果

GET /Yellow_python HTTP/1.1
‘Connection’: ‘keep-alive’,
‘Accept-Encoding’: ‘gzip, deflate, br’,
‘Accept-Language’: ‘zh-CN,zh;q=0.9’,

Pycharm正则替换

英文分词

import re
s = 'i o u! u 2?'
s = re.sub('([.!?])', ' \\1', s)  # re.sub(r'([.!?])', r' \1', s)
print(s)

i o u ! u 2 ?

2、补充一些re基础

分组

import re
text = '鸡蛋10元6个，咸蛋9元11个'
pattern = '(?P<cost>\d+)元(?P<count>\d+)个'
ls = re.findall(pattern, text)
print(ls)

[(‘10’, ‘6’), (‘9’, ‘11’)]

import re
text = '鸡蛋10元6个'
pattern = '(?P<cost>\d+)元(?P<count>\d+)个'  # 给分组命名
SRE_Match = re.search(pattern, text)
print(SRE_Match.groups())
print(SRE_Match.group('cost'))
print(SRE_Match.group('count'))

(‘10’, ‘6’)
10
6

re.sub

• sub(pattern, repl, string, count=0, flags=0)

参数	解析
pattern	正则中的模式字符串
repl	替换的字符串，也可为一个函数
string	要被查找替换的原始字符串。
count	替换的最大次数，默认全部替换

import re
text = '9-12k/月'
pat = '(?P<digit>\d+)'

def double(re_obj):
    salary = int(re_obj.group('digit'))
    return str(salary * 2)

rs = re.sub(pat, double, text)
print(rs)

18-24k/月