HDU 1727 Hastiness纯粹的英文单词拼写（就当背英文数字的单词啦）

Sun_AC

于 2014-08-15 18:58:13 发布

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分类专栏： HDU 文章标签： HDU

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本文提供了一段ACM竞赛题目的解决方案，该程序将整数转换为英文表述，覆盖了从0到999999的范围。通过使用预定义的数组来表示个位数、十位数及特定的英文词汇，实现了简洁高效的转换。

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题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1727

AC代码：

#include <stdio.h>
char a[21][10]={
"zero","one","two","three","four","five",
"six","seven","eight","nine","ten",
"eleven","twelve","thirteen","fourteen", "fifteen",
"sixteen","seventeen","eighteen","nineteen","twenty"
};
char b[10][10]={
"twenty","thirty","forty","fifty",
"sixty","seventy","eighty","ninety"
};
int main(){
	int n,q;
	while(~scanf("%d",&n)){
		if(!n){
			printf("zero\n");
			continue;
		}
		if(n>=1000){
			q=n/1000;
			printf("%s thousand",a[q]);
			n-=q*1000;
			if(!n){
				printf("\n");
				continue;
			}
			printf(" and ");
		}
		if(n>=100){
			q=n/100;
			printf("%s hundred",a[q]);
			n-=q*100;
			if(!n){
				printf("\n");
				continue;
			}
			printf(" and ");
		}
		if(n){
			if(n<=20)
				printf("%s\n",a[n]);
			else
			{
				q=n/10;
				printf("%s",b[q-2]);
				n-=q*10;
				if(!n){
					printf("\n");
					continue;
				}
				printf ("-%s\n", a[n]);
			}
		}
	}
	return 0;
}