https://leetcode-cn.com/problems/min-stack/solution/shi-yong-fu-zhu-zhan-tong-bu-he-bu-tong-bu-python-/
方法一:辅助栈和数据栈同步
import java.util.Stack;
class MinStack {
private Stack<Integer> data;
private Stack<Integer> helper;
/** initialize your data structure here. */
public MinStack() {
data = new Stack<>();
helper = new Stack<>();
}
public void push(int x) {
data.add(x);
if (helper.isEmpty() || helper.peek() >= x) {
helper.add(x);
} else {
helper.add(helper.peek());
}
}
public void pop() {
helper.pop();
data.pop();
}
public int top() {
return data.peek();
}
public int getMin() {
return helper.peek();
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
方法二:辅助栈和数据栈不同步
import java.util.Stack;
class MinStack {
private Stack<Integer> data;
private Stack<Integer> helper;
/** initialize your data structure here. */
public MinStack() {
data = new Stack<>();
helper = new Stack<>();
}
public void push(int x) {
data.add(x);
if (helper.isEmpty() || helper.peek() >= x) {
helper.add(x);
}
}
public void pop() {
// int top = data.pop();
// if (top == helper.peek()) {
// helper.pop();
// }
if ((int) helper.peek() == data.peek()) {
helper.pop();
data.pop();
} else {
data.pop();
}
}
public int top() {
return data.peek();
}
public int getMin() {
return helper.peek();
}
}
/**
* Your MinStack object will be instantiated and called as such:
* MinStack obj = new MinStack();
* obj.push(x);
* obj.pop();
* int param_3 = obj.top();
* int param_4 = obj.getMin();
*/
本文详细介绍了一种高效的数据结构——最小栈的两种实现方法。一种是辅助栈和数据栈同步更新,确保每次操作都能快速获取当前栈中最小元素;另一种是不同步更新方式,通过条件判断减少不必要的辅助栈操作,提高效率。这两种方法都在Java环境下进行了实现,适用于需要频繁获取最小值的场景。
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