1050 String Subtraction

计算字符串差异：去除字符并输出剩余字符串

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本文介绍了一种方法，通过输入两个字符串，计算第一个字符串中去除第二个字符串后剩余的字符，并以简洁的方式展示结果。

Given two strings S₁ and S₂, S = S₁ - S₂ is defined to be the remaining string after taking all the characters in S₂ from S₁. Your task is simply to calculate S₁ - S₂ for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S₁ and S₂, respectively. The string lengths of both strings are no more than 10⁴. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S₁ - S₂ in one line.

Sample Input:

They are students.
aeiou

Sample Output:

Thy r stdnts.

#include<iostream>
#include<string>
using namespace std;
int main(){
	for(string s1;getline(cin,s1);){
		string s2;
		getline(cin,s2);
		int flag[257]={0};
		for(int i = 0;i < s2.length();i++){
			flag[s2[i]] = 1;
		}
		for(int i = 0; i < s1.length();i++){
			if(!flag[s1[i]]){
				cout<<s1[i];
			}
		}
		cout<<endl;
	}
	return 0;
}