Codeforces Round #306 (Div. 2), problem: (A) Two Substrings

A. Two Substrings

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given string s. Your task is to determine if the given string s contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).

Input

The only line of input contains a string s of length between 1 and 105 consisting of uppercase Latin letters.

Output

Print "YES" (without the quotes), if string s contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise.

Sample test(s)

input

ABA

output

NO

input

BACFAB

output

YES

input

AXBYBXA

output

NO

Note

In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".

In the second sample test there are the following occurrences of the substrings: BACFAB.

In the third sample test there is no substring "AB" nor substring "BA".

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用 continue 容易错

#include<cstdio>
#include<iostream>
#include<cstring>
#include<string>
using namespace std;
string s,str;

int main(){
while(cin>>s){
    int len=s.length();
    int flag1=0,flag2=0,flag3=0,flag4=0;
    for(int i=0;i<len;){
        int k=i;
        if(i<=len-3){
            str=s.substr(i,3);
            if(str=="ABA"||str=="BAB")   flag3=1,i+=3;
        }
        if(i<=len-2&&s[i]=='A'&&s[i+1]=='B')   flag1=1,i+=2;
        if(i<=len-2&&s[i]=='B'&&s[i+1]=='A')   flag2=1,i+=2;

        if(k==i) i++;
        if(flag1&&flag2||(flag3&&(flag1||flag2))) { flag4=1; break; }
    }
    if(flag4) printf("YES\n");
    else printf("NO\n");
}
return 0;
}