1005 Spell It Right (20)（20 分）

最新推荐文章于 2025-04-26 22:36:52 发布

原创最新推荐文章于 2025-04-26 22:36:52 发布 · 595 阅读

0 ·

CC 4.0 BY-SA版权

oj-----PAT 甲级专栏收录该内容

20 篇文章

订阅专栏

本文介绍了一个简单的程序设计问题：给定一个非负整数N，计算其所有数字之和，并将该和的每个数字用英文单词输出。文章提供了一段C++代码实现，能够处理不超过10^100的大整数。

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10^100^).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:

Sample Output：

one five

这题还是很简单的但是我忘了把0判断一下其实这时候就体现出来了 do_while的好处了 17分

AC代码

#include<bits/stdc++.h>
using namespace std;
string num[20]={"zero","one","two","three","four","five","six","seven","eight","nine"};
stack<int>p;
int main()
{
    ios::sync_with_stdio(false);
    string s;
    while(cin>>s){
         while(!p.empty()) p.pop();
         long long int sum=0;
         for(int i=0;s[i];i++){
            sum+=s[i]-'0';
         }
        if(sum==0){
            cout<<"zero"<<endl;
            return 0;
        }

         while(sum){
              p.push(sum%10);
              sum/=10;
         }
         int flag=0;
         while(!p.empty()){
             if(flag) cout<<" ";
             cout<<num[p.top()];
             p.pop();
             flag=1;
         }
         cout<<endl;
    }
    return 0;
}