1005 Spell It Right (20)（20 分）

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本文介绍了一种解决大数英语数字求和及输出的方法。输入一个非负整数N，计算所有数字之和，并将该和的每一位数字转换为英文单词输出。文章提供了具体的输入输出规范，并附带了一个C++实现示例。

题目：

反思：

代码：

题目：

Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10^100^).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:
12345
Sample Output:
one five

反思：

N的取值非常大，不能直接用int

代码：

#include<iostream>
#include<iomanip>
#include<algorithm>
#include<vector>
#include<queue>
#include<string>
#include<map>
#include<list>
#include<set>
using namespace std;
int main()
{
	int n = 0, i = 0;
	string s, change[10] = { "zero","one","two","three","four","five","six","seven","eight","nine" };
	cin >> s;
	for (i = 0; i < s.size(); i++)n += s[i] - '0';
	s = to_string(n);
	for (i = 0; i < s.size(); i++)
	{
		if (i)cout << ' ';
		cout << change[s[i] - '0'];
	}
	return 0;
}