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C语言怎么把字符数字转化成数字数字转化为字符？

char   ch   =   '7 '; 
int   nch   =   ch   -   '0 '; 
int   n   =   7; 
char   chn   =   n   +   '0 ';

#include <iostream>
using namespace std;
int main()
{
int i=300;
int j;
for (j=15;j>=0;j--)
{
       if(((1<<j)&1)!=0)
              cout<<1<<endl;
       else
              cout<<0<<endl;
}
return 0;
}

输出结果最后一个是1 其他全部是0

#include <iostream>
using namespace std;
class a{
public:
       a(){
              cout<<"a+";
       }
       ~a()
       {
       cout<<"a-";
       }
};
class c{
public:
       c(){
              cout<<"c+";
              }
       ~c(){
              cout<<"c-";
       }
       };
class b:public a{
public:
       b()
       {
              cout<<"b+";
                     }
       ~b(){
              cout<<"b-";
       }
       c c1;
};
int main()
{
       b b1;
       return 0;
}

输出：a+c+b+b-c-a-

#include <iostream>
using namespace std;


int main()
{
       char const*s="hello,baofenger";
       char a[16];
       strcpy(s,a);
       return 0;
}

 #include <string.h>

  char *strcpy( char *to, const char *from );

 

“strcpy”: 不能将参数 1 从“const char *”转换为“char *”

#include <iostream>
using namespace std;
#include <cstring>
int main()
{
       inta[3][4]={{1,2,3,4},{5,6,7,8},{9,10,11,12}};
       cout<<*a[0]<<endl;
       cout<<a[1][3]<<endl;
       cout<<**(a+0)<<endl;
       cout<<*(*a+2)+2<<endl;
       cout<<*(*(a+2))+2<<endl;
       return 0;
}

输出1 8 1 5 11

关于海量用户积分排名的算法

参考地址：http://www.cnblogs.com/weidagang2046/archive/2012/03/01/massive-user-ranking.html