杭电 acm 2055 An Easy Problem

最新推荐文章于 2020-10-24 23:04:56 发布

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本文介绍了一个简单的编程问题：根据字母的大小写返回对应的数值，并加上给定的整数。使用C++实现，通过输入字母和数字，输出计算后的结果。

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An easy problem
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 28652 Accepted Submission(s): 18671

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

Output

for each case, you should the result of y+f(x) on a line.

Sample Input

6
R 1
P 2
G 3
r 1
p 2
g 3

Sample Output

19
18
10
-17
-14
-4

Author

8600

#include<iostream>
#include<string.h>
#include<string>
using namespace std;
int main()
{
	char s;
	int a,sum;
	cin>>a;
	while(a--)
	{
		int b;
		cin>>s>>sum;
		if(s>=97)
		b=(s-96)*(-1);
		else
		b=s-64;
		cout<<b+sum<<endl;
		
	 } 
	return 0;
}