1083 List Grades (25 分)-优快云博客

本文链接：https://blog.youkuaiyun.com/Tropine/article/details/120476831

该博客介绍了一个C++代码实现，用于对包含学生姓名、ID和成绩的记录列表进行排序，并根据给定的成绩区间筛选出符合条件的学生记录。代码首先按成绩降序排列所有记录，然后输出处于指定成绩范围内的学生信息。如果没有任何学生的成绩在范围内，则输出'NONE'。

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1083 List Grades (25 分)

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output NONE instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

Analysis

签到题，甚至都不需要考虑 grade 相等的情况。

Code(C++)

#include <iostream>
#include <algorithm>
using namespace std;

struct student
{
    string name;
    string id;
    int grade;
};
typedef struct student Stu;

bool cmp(Stu a, Stu b)
{
    return a.grade > b.grade;
}

int main()
{
    int n;
    cin >> n;
    
    Stu stu[n];
    for(int i=0; i<n; i++)
        cin >> stu[i].name >> stu[i].id >> stu[i].grade;
    
    sort(stu, stu+n, cmp);
    bool flag = false;
    int grade1, grade2;
    cin >> grade1 >> grade2;
    for(int i=0; i<n; i++)
    {
        if(stu[i].grade >= grade1 && stu[i].grade <= grade2)
        {
            flag = true;
            cout << stu[i].name << " " << stu[i].id << endl;
        }
    }
    if(!flag)
        cout << "NONE" << endl;
}