Hdu 2105

本文介绍了一个简单的数学问题:如何计算由三个已知坐标点构成的三角形的重心坐标,并提供了一段C++代码实现。

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Problem Description
Everyone know the story that how Newton discovered the Universal Gravitation. One day, Newton walked
leisurely, suddenly, an apple hit his head. Then Newton discovered the Universal Gravitation.From then
on,people have sovled many problems by the the theory of the Universal Gravitation. What's more, wo also
have known every object has its Center of Gravity.
Now,you have been given the coordinates of three points of a triangle. Can you calculate the center
of gravity of the triangle?
 

Input
The first line is an integer n,which is the number of test cases.
Then n lines follow. Each line has 6 numbers x1,y1,x2,y2,x3,y3,which are the coordinates of three points.
The input is terminated by n = 0.
 

Output
For each case, print the coordinate, accurate up to 1 decimal places.
 

Sample Input
2 1.0 2.0 3.0 4.0 5.0 2.0 1.0 1.0 4.0 1.0 1.0 5.0 0
 

Sample Output
3.0 2.7 2.0 2.3

 

简单的数学题;

代码:

#include<iostream>
#include<cstdio>

using namespace std;

struct point
{
       double x,y;
};
 
int main(void)
{
    struct point point1,point2,point3,Gpoint;
    int n;
    
    while(scanf("%d",&n),n)
    {
         while(n--)
         {
              scanf("%lf%lf%lf%lf%lf%lf",&point1.x,&point1.y,&point2.x,&point2.y,&point3.x,&point3.y);
              Gpoint.x = (point1.x+point2.x+point3.x)/3.0;
              Gpoint.y = (point1.y+point2.y+point3.y)/3.0;
              printf("%.1lf %.1lf\n",Gpoint.x,Gpoint.y);
         }
    }
    
    return 0;
}

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