两数之和，数组中的数字转化为十进制，相加，倒过来输出

public class 两数之和 {
    public static void main(String[] args) {
        两数之和 t=new 两数之和();
        System.out.println("输入第一个数组，空格隔开");
        int arr1[]=t.arr();
        int sum1=0;
        int sum2=0;
        for(int i=0;i<arr1.length;i++){
            sum1 = sum1+(int) (arr1[i]*(Math.pow(10,arr1.length-(i+1))));
        }
        System.out.println("输入第二个数组，空格隔开");
        int arr2[]=t.arr();
        for ( int i=0;i<arr2.length;i++){
            sum2 = sum2+(int) (arr2[i]*(Math.pow(10,arr1.length-(i+1))));
        }
        int sum=sum1+sum2;
        String ssum=String.valueOf(sum);
        String sumarry[] = ssum.split("");
        for(int i=0;i<sumarry.length;i++){
            if(i==sumarry.length-(i+1)) break; //奇数临界条件
            if(i>sumarry.length-(i+1)) break; //偶数临界条件
            String c=sumarry[sumarry.length-(i+1)];
            sumarry[sumarry.length-(i+1)] =sumarry[i];
            sumarry[i]=c;
        }
        for (String a:sumarry){
            System.out.print(a);
        }
    }
    public int[] arr (){
        Scanner sc = new Scanner(System.in);
        String inputString = sc.nextLine();
        String stringArray[] = inputString.split(" ");
        int intarr[]=new int[stringArray.length];
        for (int i=0;i<stringArray.length;i++){
            intarr[i]=Integer.parseInt(stringArray[i]);
        }
        return intarr;
    }
}

例子：
和力扣第二题类似，不过这里没有到链表。