*1001. A+B Format (20)
时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
Calculate a + b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input
Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.
Output
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input
-1000000 9
Sample Output
-999,991
AC代码:
#include<stdio.h>
int a, b, c, flag, s[20], tot = 0;
int main()
{
scanf("%d%d", &a, &b);
c = a + b; if (c < 0) { flag = 1; c = -c; }
while (c) s[tot++] = c % 10, c /= 10;
if (flag) printf("-");
for (int i = tot - 1; i >= 0; i--)
{
printf("%d", s[i]);
if (i % 3 == 0 && i) printf(",");
}
if (!tot) printf("0");
printf("\n");
return 0;
}
本文介绍了一个编程题目,要求计算两个整数a和b的和,并将结果以标准格式输出,即每三位数字用逗号分隔。文章提供了输入输出样例及通过此题目的C语言代码实现。

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