PROBLEM:
Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.
Example:
Input: The root of a Binary Search Tree like this: 5 / \ 2 13 Output: The root of a Greater Tree like this: 18 / \ 20 13
SOLVE:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def convertBST(self, root):
"""
:type root: TreeNode
:rtype: TreeNode
"""
vals=[]
self.sumv=0
def finding(root):
if not root: return
finding(root.left)
vals.append(root.val)
finding(root.right)
finding(root)
def convert(root):
if not root: return
convert(root.right)
self.sumv+=vals.pop()
root.val=self.sumv
convert(root.left)
convert(root)
return root此解中:类方法中还可以定义普通函数及调用,其中普通变量需要创建为 self.xxx(类属性)才能在普通函数中调用,而list不需要(长知识了)
本文介绍了一种将二叉搜索树(BST)转换为Greater Tree的方法。通过此转换,每个节点的值变为原值加上所有大于该值节点的值之和。文章详细描述了两步过程:首先收集BST中所有节点的值,然后根据这些值更新每个节点。
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