统计出生天数（改进前）

最新推荐文章于 2025-07-25 15:21:10 发布

原创最新推荐文章于 2025-07-25 15:21:10 发布 · 702 阅读

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#include<stdio.h>

int birthdays();//计算从出生日到现在的总天数
int sum();//计算某一年到某一年的总天数
int count();//计算闰年与非闰年某一天为该年第几天
int	number();//计算第n月m天为该年第几天的函数
int check();
int door=0;


int main()
{
	int Year1;
	int Month1;
	int Date1;
	int Year2;
	int Month2;
	int Date2;
	int Days=0;
	printf("请输入您的出生日期:year-math-day\n");
	scanf("%d-%d-%d",&Year1,&Month1,&Date1);
	printf("请输入您当前的日期:\nyear-math-day\n");
	scanf("%d-%d-%d",&Year2,&Month2,&Date2);
	Days=birthdays(Year1,Year2,Month1,Month2,Date1,Date2);
	if(door<=0)
	{
		printf("今天是你出生后的第%d天",Days);

	}
	
}

int birthdays(int Year1,int Year2,int Month1,int Month2,int Date1,int Date2)
{
	int Sumdays;
	if(Year1<Year2)
	{
		Sumdays=sum(Year1,Year2)+count(Year2,Month2,Date2)-count(Year1,Month1,Date1);
		return Sumdays;
	}
	else if(Year1>Year2)
	{
		printf("输入有误!");
		door=1;
	}
}

int sum(int Year1,int Year2)
{
	int n,Days=0;


	for(n=Year1;n<Year2;n++)
	{
		if (((n%100!=0) && (n%4==0)) || (n%400==0))
		{
			Days+=366;
		}
		else
		{
			Days+=365;
		}
	}
	return Days;
}
int count(int Year,int Month,int Date)
{
	int Days=0;
	int flg;

	if ((Year%100!=0) && (Year%4==0) || (Year%400==0))
	{
		flg=1;
		check(Month,Date,flg);
 		Days+=number(Month,Date,flg);			
	}

	else
	{	flg=0;
		check(Month,Date,flg);
		Days+=number(Month,Date,flg)-1;
	}

	return Days;
}


int number(int Month,int Date)
{
	int Days=0;
	switch (Month)
	{
	case 1:
		Days+=Date;
			break;
	case 2:
		Days=31+Date;
			break;
	case 3:
		Days=60+Date;
			break;
	case 4:
		Days=91+Date;
			break;
	case 5:
		Days=121+Date;
			break;
	case 6:
		Days=152+Date;
			break;
	case 7:
		Days=182+Date;
			break;
	case 8:
		Days=213+Date;
			break;
	case 9:
		Days=244+Date;
			break;
	case 10:
		Days=274+Date;
			break;
	case 11:
		Days=305+Date;
			break;
	case 12:
		Days=335+Date;
		break;
	default:
		printf("您输入的信息有误，请重新输入");
	}
	return Days;
}

int check(int Month,int Date,int flg)
{
	switch (Month)
	{
	case 1:
		if(Date>31)
		{
			door=1;
		}
		break;
	case 2:
		if(flg)
		{
			if (Date>29)
			{
				printf("您输入的信息有误闰年2月不会大于29天！");
			}				door=1;
		}
		else if(flg<1)
		{
			if (Date>28)
			{
			}
			printf("您输入的信息有误！非闰年二月不会大于28天");
			door=1;
		}
		break;
	case 3:
		if(Date>31)
		{
				door=1;
		}
		break;
	case 4:
		if(Date>30)
		{
				door=1;
		}
		break;
	case 5:
		if(Date>31)
		{
				door=1;
		}
		break;
	case 6:
		if(Date>30)
		{
				door=1;
		}
		break;
	case 7:
		if(Date>31)
		{
			door=1;
		}
		break;
	case 8:
		if(Date>31)
		{
			door=1;
		}
		break;
	case 9:
		if(Date>30)
		{
			door=1;
		}
		break;
	case 10:
		if(Date>31)
		{
			door=1;
		}
		break;
	case 11:
		if(Date>30)
		{
			door=1;
		}
		break;
	case 12:
		if(Date>31)
		{
			door=1;
		}

	}
	return door;
}