Mr. Kitayuta has just bought an undirected graph consisting of n vertices and m edges. The vertices of the graph are numbered from 1 to n. Each edge, namely edge i, has a color ci, connecting vertex ai and bi.
Mr. Kitayuta wants you to process the following q queries.
In the i-th query, he gives you two integers — ui and vi.
Find the number of the colors that satisfy the following condition: the edges of that color connect vertex ui and vertex vi directly or indirectly.
The first line of the input contains space-separated two integers — n and m (2 ≤ n ≤ 100, 1 ≤ m ≤ 100), denoting the number of the vertices and the number of the edges, respectively.
The next m lines contain space-separated three integers — ai, bi (1 ≤ ai < bi ≤ n) and ci (1 ≤ ci ≤ m). Note that there can be multiple edges between two vertices. However, there are no multiple edges of the same color between two vertices, that is, if i ≠ j, (ai, bi, ci) ≠ (aj, bj, cj).
The next line contains a integer — q (1 ≤ q ≤ 100), denoting the number of the queries.
Then follows q lines, containing space-separated two integers — ui and vi (1 ≤ ui, vi ≤ n). It is guaranteed that ui ≠ vi.
For each query, print the answer in a separate line.
4 5 1 2 1 1 2 2 2 3 1 2 3 3 2 4 3 3 1 2 3 4 1 4
2 1 0
5 7 1 5 1 2 5 1 3 5 1 4 5 1 1 2 2 2 3 2 3 4 2 5 1 5 5 1 2 5 1 5 1 4
1 1 1 1 2
Let's consider the first sample.

- Vertex 1 and vertex 2 are connected by color 1 and 2.
- Vertex 3 and vertex 4 are connected by color 3.
- Vertex 1 and vertex 4 are not connected by any single color.
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <cctype>
#include <queue>
#include <vector>
#define INF 0x7fffffff
#define eps (1e-9)
#define lenq 2<<16
#define maxn 199999999
#define clearto(s,x) memset(s,x,sizeof(s))
using namespace std;
int n, m, tot=0;
int edge[110][110][110]={0};
int vis[110];
int dfs(int a,int b,int t)
{
if(edge[a][b][t]==1) return 1;
int i;
for(i=1;i<=n;i++){
if(edge[a][i][t]==0) continue;
if(vis[i]==1) continue;
vis[i]=1;
if(dfs(i,b,t)==1) return 1;
}
return 0;
}
int main()
{
//freopen("E:\DATA.txt","r",stdin);
//int TT=1,tt=1; scanf("%d",&TT);
int i=0,j=0,k=0,t=0;
scanf("%d %d",&n,&m);
int a,b,c;
for(i=1;i<=m;i++){
scanf("%d %d %d",&a,&b,&c);
edge[a][b][c]=edge[b][a][c]=1;
}
scanf("%d",&tot);
while(tot--){
scanf("%d %d",&a,&b);
int ans=0;
for(t=1;t<=m;t++){
clearto(vis,0);
vis[a]=1;
if(dfs(a,b,t)==1) { ans++; edge[a][b][t]=edge[b][a][t]=1; }
}
printf("%d\n",ans);
}
return 0;
}