LeetCode 506. Relative Ranks

本文介绍了一个简单但易错的算法问题:根据运动员的成绩找出他们的相对排名,并为前三名分配金牌、银牌和铜牌。通过示例说明了输入输出格式及预期解释。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Given scores of N athletes, find their relative ranks and the people with the top three highest scores, who will be awarded medals: “Gold Medal”, “Silver Medal” and “Bronze Medal”.
Example 1:
Input: [5, 4, 3, 2, 1]
Output: [“Gold Medal”, “Silver Medal”, “Bronze Medal”, “4”, “5”]
Explanation: The first three athletes got the top three highest scores, so they got “Gold Medal”, “Silver Medal” and “Bronze Medal”.
For the left two athletes, you just need to output their relative ranks according to their scores.
Note:
N is a positive integer and won’t exceed 10,000.
All the scores of athletes are guaranteed to be unique.
Subscribe to see which companies asked this question.

这个题目看起来挺简单的,但一不小心就会掉坑里去。下面是楼主自己写的,作为一个leetcode新手,希望大家多多指教。
class Solution {
public:
vector findRelativeRanks(vector& nums) {
vector result(nums.size());
int n = nums.size();
const string s1 = “Gold Medal”;
const string s2 = “Silver Medal”;
const string s3 = “Bronze Medal”;
int *hash_table = new int[65535000];
for(int i = 0; i

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值