C++从入门到放弃 - 译回密码问题

C++从入门到放弃 - 译回密码

原题：
给定一幅密电，该电文由A->Z B-Y C-X a->z b-y c-x 规律打乱，编写逻辑将密电译回原文
相关操作：字符串和字符数组的处理

	string str = "ZYXzyxabcdefghijklmnopqrstuvwxyzLMNIPQRST";
	for (int i = 0; i < str.length()-1; i++)
	{
		if (str[i] >= 'A' && str[i] <= 'Z') {
			int cur = (25 - (('Z' - str[i])*2));
			cout << char(str[i] - cur) << '\n' << endl;
		}
		else if (str[i]>'Z' && str[i] >= 'a' && str[i] <= 'z') {
			int cur = (25 - (('z' - str[i]) * 2));
			cout << char(str[i] - cur) << '\n' << endl;
		}
		else {
		}
	}

自行探索解题，如有错漏敬迎指正