Java代码基础算法练习-三角形判断-2024.07.21

任务描述：

---

解决思路：

一个函数，带入输入的三个边长参数，条件满足计算其周长、面积，否则不计算

---

代码示例：

package a4_2024_07;

import java.util.Scanner;

public class j240721_2 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("请输入三角形的3条边 a, b, c :");
        int num01 = sc.nextInt();
        int num02 = sc.nextInt();
        int num03 = sc.nextInt();
        boolean result = method(num01, num02, num03);
        if (result) {
            System.out.println("三条边能构成三角形");
            double perimeter = num01 + num02 + num03;
            double s = perimeter / 2;
            double area = Math.sqrt(s * (s - num01) * (s - num02) * (s - num03));
            System.out.printf("面积为:%.2f", area);
            System.out.println();