一、491 递增子序列
class Solution {
private:
vector<vector<int>>result;
vector<int>path;
void backtracking(vector<int>& nums,int startindex){
if(path.size()>1)
result.push_back(path);
unordered_set<int> uset;
for(int i=startindex;i<nums.size();i++){
if(!path.empty()&&nums[i]<path.back()||uset.find(nums[i])!=uset.end())
continue;
uset.insert(nums[i]);
path.push_back(nums[i]);
backtracking(nums,i+1);
path.pop_back();
//uset不用回溯,因为每递归一次就会创建一个新的uset
}
}
public:
vector<vector<int>> findSubsequences(vector<int>& nums) {
backtracking(nums,0);
return result;
}
};
二、46 全排列
class Solution {
private:
vector<vector<int>>result;
vector<int>path;
void backtracking(vector<int>& nums,vector<bool>&used){
if(path.size() == nums.size()){
result.push_back(path);
return;
}
for(int i=0;i<nums.size();i++){
if(used[i]==true)
continue;
path.push_back(nums[i]);
used[i] = true;
backtracking(nums,used);
path.pop_back();
used[i] = false;
}
}
public:
vector<vector<int>> permute(vector<int>& nums) {
vector<bool>used(nums.size(),false);
backtracking(nums,used);
return result;
}
};
三、47 全排列||
class Solution {
private:
vector<vector<int>>result;
vector<int>path;
void backtracking(vector<int>& nums,vector<bool>&used){
if(path.size()==nums.size()){
result.push_back(path);
return;
}
for(int i=0;i<nums.size();i++){
if(i>0&&nums[i]==nums[i-1]&&used[i-1]==false)
continue;
if(used[i]==false){
used[i] = true;
path.push_back(nums[i]);
backtracking(nums,used);
path.pop_back();
used[i] = false;
}
}
}
public:
vector<vector<int>> permuteUnique(vector<int>& nums) {
vector<bool>used(nums.size(),false);
sort(nums.begin(),nums.end());
backtracking(nums,used);
return result;
}
};