Python逻辑判断：润年与日期计算-优快云博客

本文链接：https://blog.youkuaiyun.com/SS_CC_Go/article/details/93905952

本文探讨了如何使用Python进行逻辑判断，包括如何判断一个年份是否为润年，以及计算一年中的第几天。通过对年份的数学运算和日期处理，深入理解Python的条件语句和日期模块。

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1、判断是否为润年

Year=int(input("please input year:"))
Mouth=int(input("please input mouth:"))
if (Year % 4 == 0 and Year % 100 != 0 or Year % 40 == 0):
    if (Mouth == 2):
        print("29 days")
    elif (Mouth == 1 or Mouth ==3 or Mouth ==5 or Mouth ==7 or Mouth ==8 or Mouth ==10 or Mouth ==12):
          print("31 days")
    else:
        print("30 days")
else:
    if (Mouth == 2 ):
        print("28 days")
    elif (Mouth == 1 or Mouth ==3 or Mouth ==5 or Mouth ==7 or Mouth ==8 or Mouth ==10 or Mouth ==12):
        print("31 days")
    else:
        print("30 days")

2、判断一年中的第几天

Year=int(input("please input year:"))
Mouth=int(input("please input mouth:"))
Day=int(input("please input day:"))
if (Mouth == 1):
    print("%d" %Day)
elif (Mouth == 2):
    print("%d" %(31+Day))
elif(Mouth > 2 ) :
    if(Year % 4 == 0 and (Year % 100 != 0 or Year % 400 == 0)):
        if (Mouth == 3):
            print("%d" % (30+29+Day))
        elif (Mouth == 4):
            print("%d" % (30+29+31+Day))
        elif (Mouth == 5):
            print("%d" % (30+29+31+30+Day))
        elif (Mouth == 6):
            print("%d" % (30+29+31+30+31+Day))
        elif (Mouth == 7):
            print("%d" % (30+29+31+30+31+30+Day))
        elif (Mouth == 8):
            print("%d" % (366-31-30-31-30-31+Day))
        elif (Mouth == 9):
            print("%d" % (366-31-30-31-30+Day))
        elif (Mouth == 10):
            print("%d" % (366-31-30-31+Day))
        elif (Mouth == 11):
            print("%d" % (366-31-30+Day))
        else:
            print("%d" %(366-31+Day))
    else:
        if (Mouth == 3):
            print("%d" % (30+28+Day))
        elif (Mouth == 4):
            print("%d" % (30+28+31+Day))
        elif (Mouth == 5):
            print("%d" % (30+28+31+30+Day))
        elif (Mouth == 6):
            print("%d" % (30+28+31+30+31+Day))
        elif (Mouth == 7):
            print("%d" % (30+28+31+30+31+30+Day))
        elif (Mouth == 8):
            print("%d" % (365-31-30-31-30-31+Day))
        elif (Mouth == 9):
            print("%d" % (365-31-30-31-30+Day))
        elif (Mouth == 10):
            print("%d" % (365-31-30-31+Day))
        elif (Mouth == 11):
            print("%d" % (365-31-30+Day))
        else:
            print("%d" %(365-31+Day))

python逻辑判断