Description
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:
|
2^7 |
2^6 |
2^5 |
2^4 |
2^3 |
2^2 |
2^1 |
2^0 |
|
128 |
64 |
32 |
16 |
8 |
4 |
2 |
1 |
Input
The input will have a number N (1 <= N <= 100) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
Sample Input
Sample Output
#include <cstdio>
#include <cmath>
#include <iostream>
#include <algorithm>
using namespace std;
typedef long long ll;
int main()
{
int n;
while(~scanf("%d",&n))
{
for(int t=0;t<n;t++)
{
string s;
cin>>s;
for(int i=0;i<4;i++)
{
int sum=0;
for(int j=0;j<8;j++)
{
if(s[i*8+j]=='1') sum+=pow(2,7-j);
}
if(i==0) cout<<sum;
else cout<<"."<<sum;
}
cout<<"\n";
}
}
return 0;
}
该代码实现读取输入的二进制流,并将每个32位的二进制序列转换为IPv4的点分十进制格式。程序通过分组每8位并将其转换为十进制数,然后用点号连接各部分,生成合法的IP地址。
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