72.罗马数字转整数

原创已于 2024-10-31 19:30:32 修改 · 258 阅读

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于 2024-10-31 19:29:52 首次发布

class Solution {
    public int romanToInt(String s) {
        s = s.replace("IV","a");
        s = s.replace("IX","b");
        s = s.replace("XL","c");
        s = s.replace("XC","d");
        s = s.replace("CD","e");
        s = s.replace("CM","f");
        int sum=0;
        for(int i=0;i<s.length();i++){
            if(s.charAt(i)=='I'){
                sum+=1;
            }
            if(s.charAt(i)=='V'){
                sum+=5;
            }
            if(s.charAt(i)=='X'){
                sum+=10;
            }
            if(s.charAt(i)=='L'){
                sum+=50;
            }
            if(s.charAt(i)=='C'){
                sum+=100;
            }
            if(s.charAt(i)=='D'){
                sum+=500;
            }
            if(s.charAt(i)=='M'){
                sum+=1000;
            }
            if(s.charAt(i)=='a'){
                sum+=4;
            }
            if(s.charAt(i)=='b'){
                sum+=9;
            }
            if(s.charAt(i)=='c'){
                sum+=40;
            }
            if(s.charAt(i)=='d'){
                sum+=90;
            }
            if(s.charAt(i)=='e'){
                sum+=400;
            }
            if(s.charAt(i)=='f'){
                sum+=900;
            }
        }
        return sum;
    }
}

class Solution(object):
    def romanToInt(self, s):
        s=s.replace("IV","a")
        s=s.replace("IX","b")
        s=s.replace("XL","c")
        s=s.replace("XC","d")
        s=s.replace("CD","e")
        s=s.replace("CM","f")
        sum=0
        for i in range(len(s)):
            if s[i]=='I':
                sum+=1
            if s[i]=='V':
                sum+=5
            if s[i]=='X':
                sum+=10
            if s[i]=='L':
                sum+=50
            if s[i]=='C':
                sum+=100
            if s[i]=='D':
                sum+=500
            if s[i]=='M':
                sum+=1000
            if s[i]=='a':
                sum+=4
            if s[i]=='b':
                sum+=9
            if s[i]=='c':
                sum+=40
            if s[i]=='d':
                sum+=90
            if s[i]=='e':
                sum+=400;
            if s[i]=='f':
                sum+=900
        return sum