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最新推荐文章于 2023-11-20 23:12:38 发布

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最新推荐文章于 2023-11-20 23:12:38 发布

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分类专栏： HDOJ 文章标签： ACM HDOJ水题

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Bitset
Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 17565    Accepted Submission(s): 13147


Problem Description
Give you a number on base ten,you should output it on base two.(0 < n < 1000)
 

Input
For each case there is a postive number n on base ten, end of file.
 

Output
For each case output a number on base two.
 

Sample Input
1
2
3
 

Sample Output
1
10
11
 

十进制转为二进制：以下是我的AC代码：

#include<iostream>
#include<cmath>
#include<cstring>
#include<algorithm>
const int MAXN=1010;
using namespace std;
double a[MAXN];
int main()
{
    
    int num;
    while(scanf("%d",&num)==1)
    {   int i=0;
        while(num!=0)
        {
            a[i++]=num%2;
            num/=2;
        }
        for(int j=i-1;j>=0;j--)
        cout<<a[j];
        cout<<endl;
    }
    return 0; 
}