杭电OJ A+B for Input-Output Practice (IV)

本文介绍了一个经典的编程练习题“A+B”及其解决方案。题目要求计算一组整数的总和,通过输入多个整数并输出它们的和来实现。文章提供了一段使用C语言编写的示例代码,该代码能够有效地处理输入数据,并正确地计算和输出结果。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

A+B for Input-Output Practice (IV)

 
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 25682 Accepted Submission(s): 14155
 
Problem Description
Your task is to Calculate the sum of some integers.
 
Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
 
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
 
Sample Input
4 1 2 3 4
5 1 2 3 4 5
0 
 
Sample Output
10
15
 
Author
lcy
# include <stdio.h>

int main (void)
{
    int N, Sum, i;
    scanf ("%d", &N);
    do
    {
        if (N == 0)
            break;
        else
        {
            Sum = 0;
            while (N--)
            {
                scanf ("%d", &i);
                Sum += i;
            }
            printf ("%d\n", Sum);
            scanf ("%d", &N);
        }
    }while (N != 0);

    return 0;
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值