2024年国庆假期《黑神话悟空》争夺赛 WP
根据自解及官方WP优化后的wp
Misc
1z_recover 💯（outguess解密）
重新下载附件吧 ———作者：时针
拿到手压缩包解压后得到一张图片：生瓜蛋子.png
你这瓜保熟吗()
甩进010看末尾发现KP字样
上脚本，逆序还原
import os
def reverse_file_hex_and_save(input_file_path, output_file_path):
"""
从文件尾部开始读取内容，以十六进制形式逐字节反转，并将结果写入新文件。
:param input_file_path: 输入文件路径
:param output_file_path: 输出文件路径
"""
with open(input_file_path, 'rb') as input_file, open(output_file_path, 'wb') as output_file:
# 获取文件大小
file_size = os.path.getsize(input_file_path)
byte_list = []
for position in range(file_size - 1, -1, -1): # 从文件尾部开始反向遍历
# 移动文件指针到当前位置
input_file.seek(position)
# 读取单个字节并直接追加到列表，这里不进行十六进制转换，因为最终目标是保持原样写入新文件
byte_list.append(input_file.read(1))
# 将收集的字节序列写入新文件
output_file.write(b''.join(byte_list))
# 示例用法
input_file_path = '生瓜蛋子.png' # 请替换为你的输入文件路径
output_file_path = 'flag.zip' # 输出文件的路径和名称
reverse_file_hex_and_save(input_file_path, output_file_path)
print(f"Reversed content has been saved to {output_file_path}")
脚本运行后需要密码，根据题目提示拿到密码解压：you_are_so_clever
根据里面txt文本提示：奇怪，这不是压缩包吗…怎么这么多11，等等，似乎是某种运算…
猜想此层压缩包是关于11的异或运算。上脚本：
def xor_file(input_filename, output_filename, xor_key):
# 打开输入文件，以二进制模式读取
with open(input_filename, 'rb') as infile:
# 打开输出文件，以二进制模式写入
with open(output_filename, 'wb') as outfile:
# 逐字节处理输入文件内容
for byte in infile.read():
# 将每个字节转换为整数后执行异或运算
xor_byte = byte ^ xor_key
# 将异或后的整数结果转换回字节并写入到输出文件
outfile.write(xor_byte.to_bytes(1, byteorder='big'))
# 使用一个特定的密钥，如0x5A
xor_key = 0x11
# 替换这里的文件路径为实际的输入和输出文件路径
input_filepath = 'flag.zip'
output_filepath = 'flag2.zip'
# 调用函数处理文件
xor_file(input_filepath, output_filepath, xor_key)
解压成功后得到图片：flag.jpg
甩进010看见末尾有一串base64编码：OTUyNw==
base64解码后得到：9527（某种密钥）
常用的几种方法无果后尝试outguess解密：
解密后的txt文件得到flag：
flag{C0n9ratu1ati0ns!_you_are_so_cool}
诗词 💯（时间戳隐写）
你真的会读古诗嘛？ ————作者：时针
拿到手后word隐写：文件 👉 选项 👉 显示 👉 隐藏文字
打开后看到：世界是一个巨大的压缩包
修改word文件后缀为zip，在里面把这个诗词的照片提取出来（binwalk梭哈也行）
图片甩进010看见末尾很多压缩包，binwalk/foremost梭哈
看见众多文件的时间有问题，一眼时间戳隐写，上脚本
import os
import time
origin_time = 2147483000
for i in range(0,29):
filename = "D:\\Software_Data\\VMware_Machine\\kali_sharefiles\\output\\zip\\00000718\\{0}.txt".format(i)
file_attr = os.stat(filename) #读取文件属性
create_time = int(file_attr.st_mtime) #获取创建时间
# create_time = time.strftime('%Y-%m-%d %H:%M:%S',time.localtime(create_time))#转为标准格式
key = str(create_time - origin_time)
# print(key, end = " ")
print(chr(int(key)),end = "")
# ekag{/g!Y/u_3qe_Sime_M3sseq!}
# flbh|0h"Z0v`4rf`Tjnf`N4ttfr"~
注意！！！！！这里因为出题人（时钟）的问题，固定的时间戳有两个，分别是2147483000 和 2147483001，运行后得出的答案会有两个！！！
flbh|0h"Z0v`4rf`Tjnf`N4ttfr"~
ekag{/g!Y/u_3qe_Sime_M3sseq!}
然后，，，，，，，，，纯靠脑洞拼接吧（最后的master纯靠脑洞补全）
flag{0h!Y0u_4re_Time_M4ster!}
longpy 💯（Stegosaurus隐写）
作者没有给出明确的提示 ——作者：huihuilikaile
爆破宽高得到关键线索pyc
甩进010看图片末尾标志，提取出剩下的十六进制文件，另存为flag.pyc
甩kali上反编译：
得到的反编译文件打开看看：
import base64, string
def base64_encode(input_str):
base64_chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
padding_char = "="
result = ""
padding_count = 0
input_bytes = input_str.encode()
for i in range(0, len(input_bytes), 3):
three_bytes = input_bytes[i:i + 3]
chunk_length = len(three_bytes)
if chunk_length < 3:
padding_count = 3 - chunk_length
three_bytes += b'\x00' * padding_count
four_chunks = [b >> 2 * i & 63 for i in range(0, 4) for b in iter(three_bytes)]
for chunk in four_chunks:
result += base64_chars[chunk]
if padding_count > 0:
result = result[:-padding_count]
result += padding_char * padding_count
return result
original_string = "flag"
encoded_string = base64_encode(original_string)
print(encoded_string)
str1 = "KgHoPfmcONLbTNCWS7oZ"
string1 = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZnopqrstuvwxyzabcdefghijklm+/"
string2 = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"
print(base64.b64decode(str1.translate(str.maketrans(string1, string2))))
上述代码首先定义了一个base64_encode函数来手动实现Base64编码的过程。接着，它使用这个函数对字符串"Hello, world!"进行了编码，并打印了编码后的结果。最后，代码还包含了解码一个特殊处理过的Base64字符串的部分，其中使用了字符映射来恢复原始的Base64编码格式，然后再进行解码。这里，str1是一个经过非标准Base64字符集映射的字符串，通过translate方法和maketrans创建的映射表将其转换回标准Base64格式，再通过base64.b64decode进行解码，最后输出解码后的字符串。
运行结果:
mshZbYGGGBBBnAAZAAGAAB==
b'Stegosaurus pyc'
[Finished in 124ms]
"Stegosaurus"字段猜测是Stegosaurus隐写
进行Stegosaurus解码：
flag{Pyc_to_stegosaurus}
海尔之眼 （懒得喷）
海尔之眼 ——huihuilikaile
拿到手两张图，第二张图 hrxiongdi.png 甩010，右键预览图可以更改调色和排版，看见key：15740（7还是倒着的捏捏的）
根据题目提示，甩沉默之眼silentEye，得到flag：flag{h@r_X4_Ya2}
彩蛋：
再次看文件末尾，看见图片结束后，根据文件尾50 4B 05 06判断还有一个压缩包，，往头补充十六进制：50 4B 03 04 14 00
然后单独提取这段数据或binwalk/foremost梭哈，解压密码就是刚刚的flag去括号：h@r_X4_Ya2
解压出来得到第二个flag：flag{c3ad4d3b-39f0-5675-6c6f-b56036e654d3}
1z_disk_decode 💯 (veracrypt挂载)
密钥是什么呢？——时针
或许可以换个方向观察
老老实实解：frank firmly believes that the candy was stolen by natasha
也可以上爆破（根据提示“结果转换为小写”，直接爆破小写）：
解压出来得到一张喵.png：
甩进010看见文件末尾有一串其他的东西（一眼强塞的什么数据文件）：
将图片和数据手动分离出来（记得删掉所有0），上veracrypt
挂载后加载出来会有一美(sha)丽(bi)表情包：
由于自己也用这个表情包，所以知道这个表情包不全，甩010改宽高得到flag
flag{y0u_g0t_1t}
wu_kong (XOR)
黑神话，悟空–huihuilikaile
（出题方的问题，俩解法）
1、把猴.png甩stegsolve
2、猴子猴孙甩010
发现第59个数据块文件头不全，去对应位置补全头
然后单独提取出来，保存为新的png
得到Key：Sun_WuKong
提取的时候发现猴子猴孙.png末尾有snow隐写特征：
上snow得到提示：XOR（异或）
上脚本，把刚刚带Key的图片和猴.png 进行XOR
from PIL import Image
def xor_two_images(image_path1, image_path2):
img1 = Image.open(image_path1)
img2 = Image.open(image_path2)
if img1.size!= img2.size:
raise ValueError("Images must have the same size.")
pixels1 = img1.load()
pixels2 = img2.load()
width, height = img1.size
new_img = Image.new('RGBA', (width, height))
new_pixels = new_img.load()
for y in range(height):
for x in range(width):
r1, g1, b1, a1 = pixels1[x, y]
r2, g2, b2, a2 = pixels2[x, y]
new_pixels[x, y] = (r1 ^ r2, g1 ^ g2, b1 ^ b2, a1 ^ a2)
new_img.save('xor_result1.png')
image_path1 = 'hou.png'
image_path2 = '猴.png'
xor_two_images(image_path1, image_path2)
得到flag：
flag{9ba77acb-c736-70ee-1993-0d0c2a1012ee)
看过那年的雪吗？ 💯 (oursecret解密)
图片上的汉字是某个key，注意flag格式（做过的偷偷开心吧） ————ctfshow
甩010看见图片下很多文件，foremost梭哈（binwalk可以省去伪加密的过程）
得到的压缩包甩进010，伪加密，修改加密解压后得到一堆文件
flag.txt甩进010，看末尾，加上题目名字提醒，一眼snow隐写
sonw解出来得到前半段flag：ctfshow{W1sh1ng_every0ne_4_
回到其他文件上，一眼时间戳加密，上脚本：
import os
for i in range(11):
filename = "D:\\Software_Data\\VMware_Machine\\kali_sharefiles\\output\\zip\\00003326\\{}.txt".format(i)
file_attr = os.stat(filename)#读取文件属性
alter_time = str(file_attr.st_mtime)#获取修改时间
print(chr(int(alter_time[7:10])),end='')
运行结果：key:ctfSh0w（肯定是某个加密方式的key啦）
为了查找后半段flag试过多种方法无果后，回到最初的图片上面找线索
发现图片png文件尾和其中隐藏的zip文件头之间还有一些乱码9E97BA2A，再加上刚取得的key，一眼oursecret加密特征
去掉图片最后的压缩包十六进制（不然oursecret会读取不了图片数据）
然后把图片甩进软件 oursecret
提取出一个flag.txt
JRDEWV2JKIZUKR2KJBCVGWKTJBGEUVSWIVGVIWKHIJGFOWKXJJLE2UK2IVKVES2WJZFEYR2RKZKDES22GJLFKM2DIZEEMSKGINIEUNI=
flag.txt 👉 base32 👉 base32 👉 base64 👉 base64 👉 happy_time_pl4ying}
组合起来flag：ctfshow{W1sh1ng_every0ne_4_happy_time_pl4ying}
MoreHight
作者没有留下任何提示 ——Gscsed
丢随波逐流或CRC爆破或手动调整宽高得到flag：
flag{Png_hight_hight}
FindSeed_MC
开挂：BV1NS4y117yW
种子：7848034476684517680
flag{5880616f80d73e086ec577d7ad21ef99}
Crypto
At
At ——作者：huihuilikaile
ﾟωﾟﾉ= /｀ｍ´）ﾉ ~┻━┻ //*´∇｀*/ ['_']; o=(ﾟｰﾟ) =_=3; c=(ﾟΘﾟ) =(ﾟｰﾟ)-(ﾟｰﾟ); (ﾟДﾟ) =(ﾟΘﾟ)= (o^_^o)/ (o^_^o);(ﾟДﾟ)={ﾟΘﾟ: '_' ,ﾟωﾟﾉ : ((ﾟωﾟﾉ==3) +'_') [ﾟΘﾟ] ,ﾟｰﾟﾉ :(ﾟωﾟﾉ+ '_')[o^_^o -(ﾟΘﾟ)] ,ﾟДﾟﾉ:((ﾟｰﾟ==3) +'_')[ﾟｰﾟ] }; (ﾟДﾟ) [ﾟΘﾟ] =((ﾟωﾟﾉ==3) +'_') [c^_^o];(ﾟДﾟ) ['c'] = ((ﾟДﾟ)+'_') [ (ﾟｰﾟ)+(ﾟｰﾟ)-(ﾟΘﾟ) ];(ﾟДﾟ) ['o'] = ((ﾟДﾟ)+'_') [ﾟΘﾟ];(ﾟoﾟ)=(ﾟДﾟ) ['c']+(ﾟДﾟ) ['o']+(ﾟωﾟﾉ +'_')[ﾟΘﾟ]+ ((ﾟωﾟﾉ==3) +'_') [ﾟｰﾟ] + ((ﾟДﾟ) +'_') [(ﾟｰﾟ)+(ﾟｰﾟ)]+ ((ﾟｰﾟ==3) +'_') [ﾟΘﾟ]+((ﾟｰﾟ==3) +'_') [(ﾟｰﾟ) - (ﾟΘﾟ)]+(ﾟДﾟ) ['c']+((ﾟДﾟ)+'_') [(ﾟｰﾟ)+(ﾟｰﾟ)]+ (ﾟДﾟ) ['o']+((ﾟｰﾟ==3) +'_') [ﾟΘﾟ];(ﾟДﾟ) ['_'] =(o^_^o) [ﾟoﾟ] [ﾟoﾟ];(ﾟεﾟ)=((ﾟｰﾟ==3) +'_') [ﾟΘﾟ]+ (ﾟДﾟ) .ﾟДﾟﾉ+((ﾟДﾟ)+'_') [(ﾟｰﾟ) + (ﾟｰﾟ)]+((ﾟｰﾟ==3) +'_') [o^_^o -ﾟΘﾟ]+((ﾟｰﾟ==3) +'_') [ﾟΘﾟ]+ (ﾟωﾟﾉ +'_') [ﾟΘﾟ]; (ﾟｰﾟ)+=(ﾟΘﾟ); (ﾟДﾟ)[ﾟεﾟ]='\\'; (ﾟДﾟ).ﾟΘﾟﾉ=(ﾟДﾟ+ ﾟｰﾟ)[o^_^o -(ﾟΘﾟ)];(oﾟｰﾟo)=(ﾟωﾟﾉ +'_')[c^_^o];(ﾟДﾟ) [ﾟoﾟ]='\"';(ﾟДﾟ) ['_'] ( (ﾟДﾟ) ['_'] (ﾟεﾟ+(ﾟДﾟ)[ﾟoﾟ]+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((o^_^o) +(o^_^o))+ ((ﾟｰﾟ) + (ﾟΘﾟ))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((ﾟｰﾟ) + (ﾟΘﾟ))+ ((ﾟｰﾟ) + (o^_^o))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((ﾟｰﾟ) + (o^_^o))+ ((o^_^o) - (ﾟΘﾟ))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((o^_^o) +(o^_^o))+ (ﾟｰﾟ)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((ﾟｰﾟ) + (o^_^o))+ (o^_^o)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ (ﾟΘﾟ)+ ((ﾟｰﾟ) + (ﾟΘﾟ))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((o^_^o) +(o^_^o))+ ((o^_^o) - (ﾟΘﾟ))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ (o^_^o)+ ((ﾟｰﾟ) + (o^_^o))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((o^_^o) +(o^_^o))+ (o^_^o)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ (c^_^o)+ (c^_^o)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ (ﾟΘﾟ)+ (ﾟｰﾟ)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ (o^_^o)+ ((ﾟｰﾟ) + (o^_^o))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ (o^_^o)+ ((o^_^o) - (ﾟΘﾟ))+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟｰﾟ)+ (ﾟΘﾟ)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟｰﾟ)+ (ﾟΘﾟ)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟｰﾟ)+ (ﾟΘﾟ)+ (ﾟДﾟ)[ﾟεﾟ]+(ﾟΘﾟ)+ ((ﾟｰﾟ) + (o^_^o))+ ((ﾟｰﾟ) + (ﾟΘﾟ))+ (ﾟДﾟ)[ﾟoﾟ]) (ﾟΘﾟ)) ('_');
hint:注意大小写
一眼aaencode加密
uozt{Mr_s@L_Z!!!}
放随波逐流梭哈一下，Atbash有结果
但是提示注意大小写，手动转换一下：
flag{Ni_h@O_A!!!}
shuangyuCTF-AES & Base
您收到了一段使用AES-CBC模式加密的密文 ———— 白小羽
import base64
import hashlib
from Crypto.Cipher import AES
from Crypto.Util.Padding import pad, unpad
# 固定的前8字节密钥部分（题目给出）
fixed_key_part = b'fixedpart'[:8]
# 秘密字符串的前缀（题目给出）
secret_prefix = b'secret_'
# Base64编码的密文和IV（题目给出）
encoded_data = '[lg/hfCVaU7OGl11oy7JsUzozFojJSjBmYt6BGY+sO/KCKkQxdXzHjiJP1AM0eoTH]'
# 您收到了一段使用AES-CBC模式加密的密文，同时您知道了密钥的一部分生成规则：
# 密钥的前8字节是固定的，后8字节是通过某个秘密字符串的后三位数字（000-999）与特定前缀（例如secret_）
# 进行SHA-256哈希后取前8字节得到的。您的任务是编写一个Python脚本，尝试所有可能的三位数字组合，
# 以找到正确的密钥，并解密密文，获取其中的flag。
# -----------请写出你的解密过程，获取flag-------------
# 对Base64编码的密文和IV进行解码
decoded_data = base64.b64decode(encoded_data)
received_iv = decoded_data[:16]
received_encrypted_data = decoded_data[16:]
# 暴力破解秘密字符串的后三位数字
for suffix in range(1000): # 000-999
suffix_str = f'{suffix:03d}' # 确保是三位数，例如'001'
key_part2 = hashlib.sha256(secret_prefix + suffix_str.encode()).digest()[:8]
full_key = fixed_key_part + key_part2
# 尝试使用当前密钥解密密文
try:
decrypt_cipher = AES.new(full_key, AES.MODE_CBC, received_iv)
decrypted_data = decrypt_cipher.decrypt(received_encrypted_data)
decrypted_plaintext = unpad(decrypted_data, AES.block_size)
# 检查明文是否包含'flag{'，以确认是否找到了正确的密钥
if decrypted_plaintext.startswith(b'flag{'):
print(f'Decrypted plaintext: {decrypted_plaintext.decode()}')
break # 找到正确的密钥后退出循环
except Exception as e:
# 如果解密失败（例如由于填充错误），则继续尝试下一个密钥
pass
flag{Crypto_shuangyuSec_@2024}
shuangyuCTF-XOR
让十六进制字符串在XOR的胯下现出原形 ——白小羽
# 题目
def xor_encrypt(data, key):
encrypted_data = bytearray()
for char in data:
encrypted_data.append(ord(char) ^ key)
return encrypted_data.hex() # 返回十六进制字符串作为加密结果
# 以下是使用该函数加密后的一个十六进制字符串:
encrypted_string = '7a6f796973746865666c6167'
# 加密时所用的密钥(key)是 13（注意：这只是一个示例，实际题目中可以使用不同的密钥）
# 你的任务是解密这个十六进制字符串，找出它隐藏的信息，并将其格式化为 flag{*}
# 请将你的答案以 print(f"flag{{{your_decrypted_message}}}") 的形式输出
# 答案参考
def xor_decrypt(hex_data, key):
data_bytes = bytes.fromhex(hex_data) # 将十六进制字符串转换为字节
decrypted_data = bytearray()
for byte in data_bytes:
decrypted_data.append(byte ^ key) # XOR解密
return decrypted_data.decode('utf-8') # 将解密后的字节解码为字符串
# 给定的加密十六进制字符串和密钥
encrypted_string = '7a6f796973746865666c6167'
key = 13
# 解密字符串
decrypted_string = xor_decrypt(encrypted_string, key)
# 输出解密后的结果，注意格式
print(f"flag{{{decrypted_string}}}")
flag{wbtd~yehkalj}
Base签到
签到——辰
TVpXR0NaMzNNSlFXU1lUQk5GUFVHVkNHTDQzRFFOS1lORlFXNjZMVlBVPT09PT09
base 👉 base64 👉 base32 👉 flag
flag{baibai_CTF_685Xiaoyu}
你真的喜欢CTF吗？
像是个密码，至于什么密码还需要考证呢，都试试吧？
AABABAAAAAABABBAABBAAAABBABBBABBAAAABBBABABAAABABBABAAAABABAAABAAAAABABAABBAABAB ——辰
一眼培根啦
flag{falgdoyoulikectf}
decode没有key
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
decode.txt 👉 Rot13 👉 {base32 👉 文本字符串倒序在线工具（颠倒）} * 10 👉 Rot13/Rot18
flag{flagishere}
crypto2
——辰
[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]][([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]]((!![]+[])[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+([][[]]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+!+[]]+(+[![]]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+!+[]]]+(!![]+[])[!+[]+!+[]+!+[]]+(+(!+[]+!+[]+!+[]+[+!+[]]))[(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]][([][[]]+[])[+!+[]]+(![]+[])[+!+[]]+((+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]]+[])[+!+[]+[+!+[]]]+(!![]+[])[!+[]+!+[]+!+[]]]](!+[]+!+[]+!+[]+[!+[]+!+[]])+(![]+[])[+!+[]]+(![]+[])[!+[]+!+[]])()(([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+(+(+!+[]+[+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]]+[+[]])+[])[+!+[]]+(![]+[])[!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(![]+[+[]]+([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+([][[]]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[!+[]+!+[]+[!+[]+!+[]]]+([]+[])[(![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(!![]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]]()[+!+[]+[!+[]+!+[]]]+(![]+[])[+[]]+(![]+[])[!+[]+!+[]]+(![]+[])[+!+[]]+(![]+[+[]]+([]+[])[([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+([][[]]+[])[+!+[]]+(![]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[])[+!+[]]+([][[]]+[])[+[]]+([][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]]+[])[!+[]+!+[]+!+[]]+(!![]+[])[+[]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[+!+[]+[+[]]]+(!![]+[])[+!+[]]])[!+[]+!+[]+[+[]]]+(!![]+[][(![]+[])[+[]]+([![]]+[][[]])[+!+[]+[+[]]]+(![]+[])[!+[]+!+[]]+(![]+[])[!+[]+!+[]]])[!+[]+!+[]+[+[]]]+[!+[]+!+[]+!+[]]+(!![]+[])[!+[]+!+[]+!+[]]+[!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]+!+[]]+[!+[]+!+[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一眼Jsfuck
flag{3e858ccd79287cfe8509f15a71b4c45d}
来道一元积分吧
来道一元积分吧——辰
第一步接积分：2（高数不好用软件和ai解）
第二步接编码：编码进行base58加密后得到第三步的密码 —— QcYrTZ%{cxF?VfGO-MLvOnNy`Fl}roNi%jm
得到flag：flag{I_LOVE_susu}
Forensics
好吃的可乐
提交结果为flag{BASE64} —— 不要打扰我睡觉
XX省XX市XX区XXX路XX-X号
flag{56aP5bu655yB56aP5bee5biC6byT5qW85Yy65p2o5qGl5Lic6LevMTUtMeWPtw}
China
flag格式：flag{XX省XX市XX桥} ————时针
flag{台湾省台中市海天桥}
Canada
——时针
45.4396221,-73.6501553
flag{e8e5a0a3a214bc2e393ad9aeb5aaecbb}
image
题目描述： 经纬度取小数点后三位之前。例如:55.3647278,-11.3524167；取55.364,11.352进行md5加密(32位小写)。答案格式:flag{md5加密后的坐标}——瓦达西真的很菜
35.4358533,139.6450661
flag{7a0a192c47ae21cbfb4d0b03dc842316}
Pwn、Web、Reverse
2024泷羽CTF 2024年国庆假期《黑神话*悟空》争夺赛 —— DF_S
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