查找两个排序数组的中间值--以升序数组为例

最新推荐文章于 2022-06-22 22:06:09 发布

原创最新推荐文章于 2022-06-22 22:06:09 发布 · 907 阅读

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#C++ #控制台 #查找中间值 #两个排序数组

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本文介绍了一个算法，该算法用于找到两个已排序数组的中位数。通过比较两个数组的元素并逐步缩小搜索范围，最终确定中位数的具体位置。此方法适用于不同长度的两个数组。

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</pre><pre name="code" class="cpp">int getMiddleValueOfBothAscendingArr(const int const p1[], const int len1, const int const p2[], const int len2){
	if (NULL == p1 || NULL == p2 || len1 < 1 || len2 < 1){
		return 0XFFFFFFFF;
	}
	int sS = 0;
	int sL = 0;
	int tS = 0;
	int tL = 0;
	int lenS = 0;
	int lenL = 0;
	int midS = 0;
	int midL = 0;
	int len = len1 + len2;
	const int* pS = NULL;
	const int* pL = NULL;
	if (len1 > len2){
		pS = p2;
		pL = p1;
		lenS = len2;
		lenL = len1;
	}
	else{
		pS = p1;
		pL = p2;
		lenS = len1;
		lenL = len2;
	}
	sS = 0;
	sL = 0;
	tS = lenS - 1;
	tL = lenL - 1;
	midS = (sS + tS) / 2;
	midL = (sL + tL) / 2;
	if (pS[lenS - 1] <= pL[(lenL - lenS) / 2 + 1]){
		return (pS[lenS - 1]>pL[(lenL - lenS) / 2]) ? pS[lenS - 1] : pL[(lenL - lenS) / 2];
	}
	else if (pL[lenL - 1] <= pS[0]){
		return pL[(len - 1) / 2];
	}
	cout << " middle1 = " << midS + 1 << " , middle2 = " << midL + 1 << endl;
	while (!(pS[midS - 1] <= pL[midL] && p2[midL] <= pS[midS + 1] && pL[midL - 1] <= pS[midS] && pS[midS] <= pL[midL + 1])){
		if (pS[midS] < pL[midL]){
			sS = midS;
			midS = (sS + tS + 1) / 2;
			midL -= (midS-sS);
		}
		else{
			tS = midS;
			midS = (sS + tS + 1) / 2;
			midL += (tS - midS);
		}
		cout << " middle1 = " << midS + 1 << " , middle2 = " << midL + 1 << endl;
	}
	if (pS[midS] < pL[midL]){
		return pL[midL];
	}
	else {
		return pS[midS];
	}
}