flask--基础知识点--3--secure_filename()对中文的兼容

最新推荐文章于 2024-03-25 15:04:08 发布

Raging__Fire

最新推荐文章于 2024-03-25 15:04:08 发布

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本文探讨了在Flask中使用secure_filename()函数处理中文文件名的问题，分别针对Python2和Python3环境进行了讲解。

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1 python2

# -*- coding: utf8 -*-
import re
import os

def secure_filename(filename):
    from werkzeug._compat import text_type, PY2
    if isinstance(filename, text_type):
        from unicodedata import normalize

        filename = normalize("NFKD", filename).encode("utf-8", "ignore")
        # if not PY2:
        #     filename = filename.decode("utf-8")
        filename = filename.decode("utf-8")
    for sep in os.path.sep, os.path.altsep:
        if sep:
            filename = filename.replace(sep, " ")

    _filename_ascii_strip_re = re.compile(u"[^A-Za-z0-9_\u4e00-\u9fa5.-]")
    filename = _filename_ascii_strip_re.sub("", "_".join(filename.split())).strip("._")

    # on nt a couple of special files are present in each folder.  We
    # have to ensure that the target file is not such a filename.  In
    # this case we prepend an underline
    _windows_device_files = ("CON", "AUX", "COM1", "COM2", "COM3", "COM4", "LPT1", "LPT2", "LPT3", "PRN", "NUL",)
    if (
        os.name == "nt"
        and filename
        and filename.split(".")[0].upper() in _windows_device_files
    ):
        filename = "_" + filename

    return filename

filename= u"人民*/中国abc.xlsx"
filename = secure_filename(filename)
print(filename)
print(type(filename))


"""
执行结果：
[root@lighthouse ~]# python secure_filename.py 
人民_中国abc.xlsx
<type 'unicode'>
"""

2 python3

pass