将已经转换成字符串格式的16进制字符转换成ASCII码输出

最新推荐文章于 2024-12-06 19:44:49 发布

原创最新推荐文章于 2024-12-06 19:44:49 发布 · 1.1k 阅读

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本文分享了一段C语言代码，用于将十六进制字符串转换为对应的ASCII字符。通过解析十六进制数并映射到预定义的ASCII字符数组，实现了高效准确的转换过程。

因为只需要转换一些基本的ASCII，不是全部的ASCII，如果要全部的ASCII表，可以自行拓展。

自己写的代码比较简单，就不做描述了。直接贴代码了;

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

char *Ascii[200] = {" ","!","\"","#","$","%","&","'","(",")","*","+",",","-",".","/","0","1","2","3",
"4","5","6","7","8","9",":",";","<","=",">","?","@","A","B","C","D","E","F","G","H",
"I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","[","/",
"]","^","_","`","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u",
"v","w","x","y","z","{","|","}","~"};

int AsciiToDec(char str);
int HexToStr(char *Hex, char*str);

int main()
{
   char *str = "222616263222";
   int len = 0;
   int ret = 0;
   len = strlen(str);
   char stmp[1000] = {0};
   char str_str[1000] = {0};

   if(len % 2 != 0)
   {
       printf("len is error![%d]\n", len);
   }

   ret = HexToStr(str, stmp);
   if(ret != 0)
   {
       printf("error!\n");
       return -1;
   }
   printf("stmp[%s]\n", stmp);

return 0;

}

int AsciiToDec(char str)
{
   if(str >= 'a' && str <= 'z')
   {
       return str - '0' - 39;
   }

   else if(str >= 'A' && str <= 'Z')
   {
       return str - '0' - 7;
   }
   else if(str >= '0' && str <= '9')
   {
       return str - '0';
   }
   else
   {
       return -1;
   }
}

int HexToStr(char *hex, char*str)
{
   int len_hex = 0;
   int pos = 0;
   int shiwei = 0;
   int gewei = 0;
   int sum = 0;

   len_hex = strlen(hex);

memset(str, 0x00, sizeof(str));

   for(int i = 0; i < len_hex - 1; i+=2)
   {
       shiwei = AsciiToDec(hex[i]) * 16;
       if(shiwei < 0)
       {
           return -1;
       }

       gewei = AsciiToDec(hex[i+1]);
       if(gewei < 0)
       {
           return -1;
       }

       sum = shiwei + gewei;
       pos = sum - 32;
       strcat(str, Ascii[pos]);
   }
   return 0;
}