Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- getMin() -- Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> Returns -3. minStack.pop(); minStack.top(); --> Returns 0. minStack.getMin(); --> Returns -2.
solution:
维护一个栈,获得栈中元素的的最小值
code:
class MinStack {
public:
stack<int> dataStack;
stack<int> minStack;
void push(int x) {
dataStack.push(x);
if(minStack.empty())
{
minStack.push(x);
return;
}
int min=minStack.top();
if(min<x)
{
minStack.push(min);
return;
}
minStack.push(x);
}
void pop() {
dataStack.pop();
minStack.pop();
}
int top() {
return dataStack.top();
}
int getMin() {
return minStack.top();
}
};