本题不难,下面是完整的代码
#include<iostream>
using namespace std;
int main() {
int n;
char a[100][4],b[100][4],c;
cin >> n;
for (int i = 0; i < n; i++) {
for (int j = 0; j < 4; j++) {
cin >> a[i][j] >> c >> b[i][j];
}
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < 4; j++) {
if (b[i][j] == 'T') {
if (a[i][j] == 'A')
cout << 1;
else if (a[i][j] == 'B')
cout << 2;
else if (a[i][j] == 'C')
cout << 3;
else
cout << 4;
}
}
}
return 0;
}