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最新推荐文章于 2024-12-31 11:15:59 发布

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分类专栏： Online Judge

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探讨了在已知粒子初速度、加速度和达到某一速度所需时间的情况下，如何计算在两倍时间内粒子的位移。输入包含粒子达到的速度值和对应的时间，输出则为双倍时间内的位移。

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Time limit: 3.000 seconds

A partical 【[电] 质点;】has inital velocity and accerleration【初速度与加速度】 .If its velocity after certain time is v then what will its displacement be in twice of that time ?

Input

The input will contains two integers in each line .Each line makes one set of input .These two integers denote the value of v (-100 <= v <= 100 ) and t (0<= t <=200) (t means at the time the partical gainsthat velocity)

Output

For each line of input print a single integer in one line denoting the displacement in double of that time.

Sample Input

0 0

5 12

Sample Output

120

Code: accepted

#include<iostream>
using namespace std;

int main()
{
	int v,t;
	
	while(scanf("%d%d",&v,&t)!=EOF)
	{
		cout<<v*2*t<<endl;
	}
	return 0;
}