Every day a leetcode
题目来源:100. 相同的树
解法1:递归
递归实现对两棵树的同一位置的节点的逐一比较。
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
bool isSameTree(struct TreeNode* p, struct TreeNode* q){
if(p == NULL && q == NULL) return true;
else if(p == NULL || q == NULL) return false;
else if(p->val!=q->val) return false;
else return isSameTree(p->left,q->left) && isSameTree(p->right,q->right);
}
结果: