问题
现有一直线,从原点到无穷大。
这条直线上有N个线段。线段可能相交。
问,N个线段总共覆盖了多长?(重复覆盖的地区只计算一次)
解答
用一个数组来标记区间段的覆盖情况,最后遍历这个标记数组就行了。
public class XianDuanLength {
public static void main(String[] args) {
SegMent segMent1 = new SegMent(2, 5);
SegMent segMent2 = new SegMent(7, 10);
SegMent segMent3 = new SegMent(16, 20);
SegMent segMent4 = new SegMent(9, 12);
SegMent[] segMents = { segMent1, segMent2, segMent3, segMent4 };
System.out.println(getTotalLength(segMents));
}
public static int getTotalLength(SegMent[] segMents) {
//找到最小起始点和最大终止点
boolean flag[] = new boolean[100];
int min = segMents[0].getStart();
int max = segMents[0].getEnd();
for (SegMent segMent : segMents) {
//标记区间段
for (int start = segMent.getStart(); start < segMent.getEnd(); start++) {
flag[start] = true;
}
if (segMent.getStart() < min) {
min = segMent.getStart();
}
if (segMent.getEnd() > max) {
max = segMent.getEnd();
}
}
int length = 0;
for (int i = min; i <= max; i++) {
if (flag[i]) {
while (flag[i]) {
length++;
i++;
}
}
}
return length;
}
/**
* 判断点是否在区间内
* @param point
* @param segMent
* @return
*/
public static boolean isInSegMent(int point, SegMent segMent) {
return segMent.getStart() <= point && point <= segMent.getEnd() ? true : false;
}
/**
* 区间类
*/
static class SegMent {
private int start;
private int end;
public SegMent(int start, int end) {
this.start = start;
this.end = end;
}
public int getStart() {
return start;
}
public void setStart(int start) {
this.start = start;
}
public int getEnd() {
return end;
}
public void setEnd(int end) {
this.end = end;
}
}
}
928

被折叠的 条评论
为什么被折叠?



