#include<queue>
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cctype>
#include<algorithm>
using namespace std;
int main()
{
int a,limit,cas=0;
while(scanf("%d%d",&a,&limit)!=EOF)
{
cas++;
if(a<0&&limit<0) break;
long long sum=1;
long long b=a;
while(b!=1)
{
if(b%2==0)
{
b/=2;
sum++;
}
else
{
b=b*3+1;
if(b>limit)
break;
sum++;
}
}
printf("Case %d: A = %d, limit = %d, number of terms = %lld\n",cas,a,limit,sum);
}
return 0;
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cctype>
#include<algorithm>
using namespace std;
int main()
{
int a,limit,cas=0;
while(scanf("%d%d",&a,&limit)!=EOF)
{
cas++;
if(a<0&&limit<0) break;
long long sum=1;
long long b=a;
while(b!=1)
{
if(b%2==0)
{
b/=2;
sum++;
}
else
{
b=b*3+1;
if(b>limit)
break;
sum++;
}
}
printf("Case %d: A = %d, limit = %d, number of terms = %lld\n",cas,a,limit,sum);
}
return 0;
}
本来是个水题,提交滞后竟然TLE了,刚开始以为是算法需要优化,后来才发现原来是b和sum会超int,如果不定义long long 就会超时,由此可以知道数据量定义太小也会导致超时。