关于“contiune”在C中的使用问题

#include<stdio.h>
void display(char cr, int lines, int width);
int main(void)
{
int ch;
int rows,cols;

printf("请输入一个字母和两个数字: \n");
while((ch = getchar()) != '\n')
{
	if ((scanf("%d %d", &rows, &cols)) != 2)
	    break;
	    
	display(ch, rows, cols);   
	**while (getchar() != '\n')
      {
      	 continue;// 想问一下如果执行了这个contiune 应该会跳过下面printf语句，为什么程序运行后没有跳过？
      }**  
   
	**printf("enter zhe new lines to quit \n");**     	
}
printf("Bye.\n");
return 0;

}

void display(char cr, int lines, int width)
{
int row, col;

for (row = 1; row <=lines; row++)
{
	for (col =1; col <= width; col++)
	    putchar(cr);
	putchar('\n');
}

}