Lintcode 9 Fizz Buzz

最新推荐文章于 2022-03-09 14:08:35 发布

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最新推荐文章于 2022-03-09 14:08:35 发布

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本文介绍了一个经典的编程面试题——FizzBuzz问题的解决方案。通过Java和C++两种语言演示了如何根据给定数字n打印从1到n的数字，并在数字能被3整除时打印fizz，被5整除时打印buzz，同时被3和5整除时打印fizzbuzz。提供了简洁明了的代码实现。

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Given number n. Print number from 1 to n. But:

when number is divided by 3, print "fizz".
when number is divided by 5, print "buzz".
when number is divided by both 3 and 5, print "fizz buzz".

Example

If n = 15, you should return:

[
  "1", "2", "fizz",
  "4", "buzz", "fizz",
  "7", "8", "fizz",
  "buzz", "11", "fizz",
  "13", "14", "fizz buzz"
]

java：

class Solution {
    /**
     * param n: As description.
     * return: A list of strings.
     */
    public ArrayList<String> fizzBuzz(int n) {
        ArrayList<String> results = new ArrayList<String>();
        int i = 1;
        int p3 = 1, p5 = 1;
        
        while (i <= n) {
          while (i < p3 * 3 && i < p5 * 5) {
            results.add(i + "");
            i++;
          }
        
          if (i <= n && p3 * 3 == p5 * 5) {
            results.add("fizz buzz");
            p3++;
            p5++;
            i++;
            continue;
          }
        
          while (i <= n && p3 * 3 <= i) {
            results.add("fizz");
            p3++;
            i++;
          }
        
          while (i <= n && p5 * 5 <= i) {
            results.add("buzz");
            p5++;
            i++;
          }
        }
        
        return results;
    }
}

class Solution {
    /**
     * param n: As description.
     * return: A list of strings.
     */
    public ArrayList<String> fizzBuzz(int n) {
        ArrayList<String> results = new ArrayList<String>();
        for (int i = 1; i <= n; i++) {
            if (i % 15 == 0) {
                results.add("fizz buzz");
            } else if (i % 5 == 0) {
                results.add("buzz");
            } else if (i % 3 == 0) {
                results.add("fizz");
            } else {
                results.add(String.valueOf(i));
            }
        }
        return results;
    }
}

c++：

class Solution {
public:
    /*
     * param n: As description.
     * return: A list of strings.
     */
    vector<string> fizzBuzz(int n) {
        vector<string> results;
        for (int i = 1; i <= n; i++) {
            if (i % 15 == 0) {
                results.push_back("fizz buzz");
            } else if (i % 5 == 0) {
                results.push_back("buzz");
            } else if (i % 3 == 0) {
                results.push_back("fizz");
            } else {
                results.push_back(to_string(i));
            }
        }
        return results;
    }
};