Description
In the Not-Spreading-Your-Sickness University (NSYSU), there are many student groups. Students in the same group intercommunicate with each other frequently, and a student may join several groups. To prevent the possible transmissions of SARS, the NSYSU collects the member lists of all student groups, and makes the following rule in their standard operation procedure (SOP).
Once a member in a group is a suspect, all members in the group are suspects.
However, they find that it is not easy to identify all the suspects when a student is recognized as a suspect. Your job is to write a program which finds all the suspects.
Input
A case with n = 0 and m = 0 indicates the end of the input, and need not be processed.
Output
Sample Input
100 4 2 1 2 5 10 13 11 12 14 2 0 1 2 99 2 200 2 1 5 5 1 2 3 4 5 1 0 0 0
Sample Output
4 1 1
Source
并查集的最基本也是最重要,最核心的三个操作:找该元素所在集合的根节点、合并两个集合以及判断两个元素是否属于一个集合。
#include <iostream>
#include <cstdio>
#include <map>
#include <set>
#include <vector>
#include <queue>
#include <stack>
#include <cmath>
#include <algorithm>
#include <cstring>
#include <string>
using namespace std;
#define INF 0x3f3f3f3f
#define maxn 30000
int n,m;
int parent[maxn+10];
int total[maxn+10];
int getparent(int a)
{
if(parent[a]!=a){
parent[a]=getparent(parent[a]);
}
return parent[a];
}
void Merge(int a,int b)
{
int p1=getparent(a);
int p2=getparent(b);
if(p1==p2){
return;
}
total[p1]+=total[p2];
parent[p2]=p1;
}
int main()
{
while(~scanf("%d%d",&n,&m),n+m){
for(int i=0;i<n;i++){
parent[i]=i;
total[i]=1;
}
for(int j=0;j<m;j++){
int k,s,o;
scanf("%d",&k);
scanf("%d",&s);
for(int i=1;i<k;i++){
scanf("%d",&o);
Merge(s,o);
}
}
printf("%d\n",total[getparent(0)]);
}
return 0;
}
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