C语言结构之判断今天明天日期

#include <stdio.h>
#include <stdbool.h>

struct date{
    int month;
    int day;
    int year;
};

bool isLeap(struct date d);
int numberofDays(struct date d);

int main(int argc,char const *argv[])
{
    struct date today,tomorrow;
    
    printf("Enter today's date(mm dd yyy):");
    scanf("%i %i %i",&today.month,&today.day,&today.year);
    
    if(today.day!=numberofDay(today)){
        tomorrow.day = today.day+1;
        tomorrow.month = today.month;
        tomorrow.year = today.year;
    }else if(today.month==12){
        tomorrow.day=1;
        tomorrow.month=1;
        tomorrow.year=today.year+1;
    }else{
        tomorrow.day=1;
        tomorrow.month = today.month+1;
        tomorrow.year = today.year;
    }
    printf("Tomorrow's date is %i-%i-%i.\n",tomorrow.year,tomorrow.month,tomorrow.day);
    
    return 0;
}

int numberofDay(struct date d)
{
    int days;
    const int daysPerMonth[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
    if(d.month == 2 &&isLeap(d)){
        days = 29;
    }else{
        days = 28;
    }
    return days;
}

bool isLeap(struct date d)
{
    bool leap = false;
    
    if((d.year%4==0&&d.year%100!=0)|| d.year%400 == 0)
    leap = true;
    return leap;
}