比较当前时间是否在指定范围

最新推荐文章于 2024-01-24 21:50:36 发布

原创最新推荐文章于 2024-01-24 21:50:36 发布 · 906 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#date #string

Java 专栏收录该内容

43 篇文章

订阅专栏

本文提供了一种方法来判断两个指定时间是否存在交集，通过解析字符串中的小时和分钟，将其转换为总分钟数进行比较。

    //比较两个时间是否存在交集
    public static boolean isInDates(String times){   
        int strDateBeginH = Integer.parseInt(times.split("-")[0].split(":")[0]);  
        int strDateBeginM = Integer.parseInt(times.split("-")[0].split(":")[1]);  
        int beginM = strDateBeginH*3600+strDateBeginM*60;
        System.out.println("开始时间	"+strDateBeginH+":"+strDateBeginM+"    "+beginM);
        
    	Date dt = new Date();
        int strDateH = dt.getHours();  
        int strDateM = dt.getMinutes();
        int thisM = strDateH*3600+strDateM*60;
        System.out.println("当前时间	"+strDateH+":"+strDateM+"    "+thisM);
        
        int strDateEndH = Integer.parseInt(times.split("-")[1].split(":")[0]);  
        int strDateEndM = Integer.parseInt(times.split("-")[1].split(":")[1]);  
        int endM = strDateEndH*3600+strDateEndM*60;
        System.out.println("结束时间	"+strDateEndH+":"+strDateEndM+"    "+endM);

        System.out.println("比较实际  ["+beginM+" "+thisM+" "+endM+"] "+(thisM>= beginM && thisM <= endM));
        if(thisM>= beginM && thisM <= endM){  
     	   return true;
        }else{  
            return false;  
        }  
   }	
    //比较两个时间是否存在交集
    public static boolean isInDates_old(String times){   
       Date dt = new Date();
       int strDateH = dt.getHours();  
       int strDateM = dt.getMinutes();  
       if(strDateH == 0 && strDateM == 0){
    	   strDateH = 23;strDateM = 59;
       }else if(strDateH == 0){
    	   strDateH = 24;
       }else if(strDateM == 0){
    	   strDateH = strDateH-1;strDateM = 59;
       }         
       
       int strDateBeginH = Integer.parseInt(times.split("-")[0].split(":")[0]);  
       int strDateBeginM = Integer.parseInt(times.split("-")[0].split(":")[1]);           
       
       int strDateEndH = Integer.parseInt(times.split("-")[1].split(":")[0]);  
       int strDateEndM = Integer.parseInt(times.split("-")[1].split(":")[1]);  
       if(strDateEndH == 0 && strDateEndM == 0){
    	   strDateEndH = 23;strDateEndM = 59;
       }else if(strDateEndH == 0){
    	   strDateEndH = 24;
       }else if(strDateEndM == 0){
    	   strDateEndH = strDateEndH-1;strDateEndM = 59;
       }
       
       if((strDateH>=strDateBeginH && strDateM>=strDateBeginM && strDateH<=strDateEndH && strDateM<=strDateEndM)){  
    	   return true;
       }else{  
           return false;  
       }  
   }