JAVA split 分割符连续时遇到的问题_split连续分隔符-优快云博客

本文介绍了在Java中使用`String#split`方法时，遇到连续分隔符导致结果不符合预期的问题。通过介绍limit参数的作用，提出将该参数设置为-1来实现期望的分割结果，即包含空字符串。适合处理如'132#456##'这样的字符串。

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在用split分割字符串时，当分隔符连续时如果使用默认方法则会出现问题，例如
String str = “132#456##”，这里以#分割，如果使用array = str.split("#")得到的结果会是
array = {“132” , “456”}
array.length = 2
但是有时候这并不是我们想要的结果

如果我们想要这种结果
array = {“132”,“456”,"",""}

这里给出了解决方法:

https://www.zhihu.com/question/20318493

public String[] split(String regex,int limited)

The limit parameter controls the number of times the pattern is applied and therefore affects the length of the resulting array. If the limit n is greater than zero then the pattern will be applied at most n - 1 times, the array’s length will be no greater than n, and the array’s last entry will contain all input beyond the last matched delimiter. If n is non-positive then the pattern will be applied as many times as possible and the array can have any length. If n is zero then the pattern will be applied as many times as possible, the array can have any length, and trailing empty strings will be discarded.

这里将limit参数设置为 -1 ，即可得到上述结果