944. Delete Columns to Make Sorted

本文探讨了LeetCode上的一道题——按列删除以保持字符串数组的每列字符非递减排序。通过分析,我们提供了一种解决方案,使用列表存储每列字符并检查其是否为非递减顺序,若不是则计数删除列的数量。

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https://leetcode.com/contest/weekly-contest-111/problems/delete-columns-to-make-sorted/

public int minDeletionSize(String[] A) {
        List<List<Character>> columnList = new ArrayList<>(A[0].length());
        for (int i = 0; i < A[0].length(); i++) {
            List<Character> temp = new ArrayList<>();
            for (int j = 0; j < A.length; j++) {
                temp.add(A[j].charAt(i));
            }
            columnList.add(temp);
        }
        int res = 0;
        lable:for (List<Character> col : columnList) {
            for (int i = 0; i < col.size(); i++) {
                Iterator<Character> iterator = col.iterator();
                int pre = col.get(0);
                while (iterator.hasNext()) {
                    int temp = iterator.next();
                    if (temp < pre) {
                        res ++;
                        continue lable;
                    } else {
                        pre = temp;
                    }
                }
            }
        }
        return res;
    }

We are given an array A of N lowercase letter strings, all of the same length.

Now, we may choose any set of deletion indices, and for each string, we delete all the characters in those indices.

For example, if we have a string "abcdef" and deletion indices {0, 2, 3}, then the final string after deletion is "bef".

Suppose we chose a set of deletion indices D such that after deletions, each remaining column in A is in non-decreasing sorted order.

Formally, the c-th column is [A[0][c], A[1][c], ..., A[A.length-1][c]]

Return the minimum possible value of D.length.

 

Example 1:

Input: ["cba","daf","ghi"]
Output: 1

Example 2:

Input: ["a","b"]
Output: 0

Example 3:

Input: ["zyx","wvu","tsr"]
Output: 3

Note:

  1. 1 <= A.length <= 100
  2. 1 <= A[i].length <= 1000
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