现象描述
以下情况中默认是false,设置了SetVsible后仍为false,这是什么原因
QPushButton *btn = new QPushButton(this);
qWarning()<<"isVisible="<<btn->isVisible();//false
btn->setVisible(true);
qWarning()<<"isVisible="<<btn->isVisible();//false
官网文档研究
This property holds whether the widget is visible Calling setVisible(true) or show() sets the widget to visible status if all its parent widgets up to the window are visible. If an ancestor is not visible, the widget won't become visible until all its ancestors are shown. If its size or position has changed, Qt guarantees that a widget gets move and resize events just before it is shown. If the widget has not been resized yet, Qt
本文探讨了在Qt编程中,当QWidget的isVisible属性默认为false且设置为true后仍然保持false的情况。通过研究官网文档和源码,发现如果控件的父类不可见,即使设置为可见,该属性仍会返回false。文中提供了相关代码示例和测试结果,以解释此属性在不同场景下的行为。
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