9-30每日一题

223. 矩形面积

思路：模拟

答案加上两个矩形的面积，再减去重叠部分的面积，重叠部分是一个矩形，如果该矩形不存在说明不重叠

class Solution {
public:
    int computeArea(int ax1, int ay1, int ax2, int ay2, int bx1, int by1, int bx2, int by2) {
        int res = 0;
        res += (ax2 - ax1) * (ay2 - ay1) + (bx2 - bx1) * (by2 - by1);
        int x1 = max(ax1, bx1), y1 = max(ay1, by1);
        int x2 = min(ax2, bx2), y2 = min(ay2, by2);


        if (x1 < x2 && y1 < y2) res -= (x2 - x1) * (y2 - y1);
        return res;
    }
};