显示目录结构的shell脚本

# !/bin/bash

current_path=`pwd`

output_dir()
{
   dir=$1    #dir is a globle varible
   elements=`ls $dir`
     
   echo "$2""+"${dir##/*/}    #get the dir name, remove the path
   for each in $elements
   do
      if [ -d $1"/"$each ]
      then
          output_dir $1"/"$each "$2""    "    #here, dir will be changed, and be used in the outloop
      else
          echo "$2""    " $each
      fi
   done
}

output_dir $current_path ""  # first para is directory, second para is space