LeetCode #843 - Guess the Word

本文介绍了一种在LeetCode平台上的新互动问题——猜单词游戏。玩家需要从给定的单词列表中找出一个秘密单词,每次猜测后,系统会返回猜测单词与秘密单词的匹配数量,帮助玩家逐步缩小范围,最终找到目标单词。文章详细解释了游戏规则,并提供了一个解决方案的示例。

题目描述:

This problem is an interactive problem new to the LeetCode platform.

We are given a word list of unique words, each word is 6 letters long, and one word in this list is chosen as secret.

You may call master.guess(word) to guess a word.  The guessed word should have type string and must be from the original list with 6 lowercase letters.

This function returns an integer type, representing the number of exact matches (value and position) of your guess to the secret word.  Also, if your guess is not in the given wordlist, it will return -1 instead.

For each test case, you have 10 guesses to guess the word. At the end of any number of calls, if you have made 10 or less calls to master.guess and at least one of these guesses was the secret, you pass the testcase.

Besides the example test case below, there will be 5 additional test cases, each with 100 words in the word list.  The letters of each word in those testcases were chosen independently at random from 'a' to 'z', such that every word in the given word lists is unique.

Example 1:

Input: secret = "acckzz", wordlist = ["acckzz","ccbazz","eiowzz","abcczz"]

Explanation:

master.guess("aaaaaa") returns -1, because "aaaaaa" is not in wordlist.

master.guess("acckzz") returns 6, because "acckzz" is secret and has all 6 matches.

master.guess("ccbazz") returns 3, because "ccbazz" has 3 matches.

master.guess("eiowzz") returns 2, because "eiowzz" has 2 matches.

master.guess("abcczz") returns 4, because "abcczz" has 4 matches.

We made 5 calls to master.guess and one of them was the secret, so we pass the test case.

Note:  Any solutions that attempt to circumvent the judge will result in disqualification.

/**
 * // This is the Master's API interface.
 * // You should not implement it, or speculate about its implementation
 * class Master {
 *   public:
 *     int guess(string word);
 * };
 */
class Solution {
public:
    void findSecretWord(vector<string>& wordlist, Master& master) {
        int count=10;
        while(count>0)
        {
            int i=rand()%wordlist.size();
            int match=master.guess(wordlist[i]);
            if(match==6) return;
            else wordlist=updateWordList(wordlist,wordlist[i],match);
            count--;
        }
    }
    
    int matchLetter(string a, string b)
    {
        int result=0;
        for(int i=0;i<a.size();i++) if(a[i]==b[i]) result++;
        return result;
    }
    
    vector<string> updateWordList(vector<string> wordList, string s, int match)
    {
        vector<string> result;
        // 如果匹配字符数和s不一样,必然不是目标单词,所以只选择匹配数一样的可以逐步缩小wordlist
        // 并保证目标词还在wordlist中
        for(auto word:wordList) 
            if(matchLetter(word,s)==match) result.push_back(word);
        return result;
    }
};

 

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