题目描述:
Implement FreqStack, a class which simulates the operation of a stack-like data structure.
FreqStack has two functions:
push(int x), which pushes an integerxonto the stack.pop(), which removes and returns the most frequent element in the stack.- If there is a tie for most frequent element, the element closest to the top of the stack is removed and returned.
Example 1:
Input: ["FreqStack","push","push","push","push","push","push","pop","pop","pop","pop"], [[],[5],[7],[5],[7],[4],[5],[],[],[],[]] Output: [null,null,null,null,null,null,null,5,7,5,4] Explanation: After making six .push operations, the stack is [5,7,5,7,4,5] from bottom to top. Then: pop() -> returns 5, as 5 is the most frequent. The stack becomes [5,7,5,7,4]. pop() -> returns 7, as 5 and 7 is the most frequent, but 7 is closest to the top. The stack becomes [5,7,5,4]. pop() -> returns 5. The stack becomes [5,7,4]. pop() -> returns 4. The stack becomes [5,7].
Note:
- Calls to
FreqStack.push(int x)will be such that0 <= x <= 10^9. - It is guaranteed that
FreqStack.pop()won't be called if the stack has zero elements. - The total number of
FreqStack.pushcalls will not exceed10000in a single test case. - The total number of
FreqStack.popcalls will not exceed10000in a single test case. - The total number of
FreqStack.pushandFreqStack.popcalls will not exceed150000across all test cases.
class FreqStack {
private:
unordered_map<int,stack<int>> stacks;
unordered_map<int,int> freq;
int max_freq;
public:
FreqStack() {
max_freq=0;
}
void push(int x) {
int f=freq[x];
if(f==max_freq) max_freq++;
f++;
stacks[f].push(x);
freq[x]=f;
}
int pop() {
int x=stacks[max_freq].top();
stacks[max_freq].pop();
if(stacks[max_freq].size()==0)
{
stacks.erase(max_freq);
max_freq--;
}
freq[x]--;
return x;
}
};
本文详细介绍了FreqStack类的设计与实现,这是一种模仿堆栈数据结构的类,具有push和pop功能。pop操作返回并移除堆栈中最频繁的元素,若频率相同,则移除最接近顶部的元素。通过实例演示了其工作原理。
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