完善的复数类
1、复数类应该具有的操作
- 运算:+,-,*,/
- 比较:==,!=
- 赋值:=
- 求模:modulus
2、利用操作符重载
Complex operator + (const Complex& c);
Complex operator - (const Complex& c);
Complex operator * (const Complex& c);
Complex operator / (const Complex& c);
bool operator == (const Complex& c);
bool operator != (const Complex& c);
Complex& operator = (const Complex& c);
3、编程实验
//Complex.h
#ifndef _COMPLEX_H_
#define _COMPLEX_H_
class Complex
{
double a;
double b;
public:
Complex(double a = 0, double b = 0);
double getA();
double getB();
double getModulus();
Complex operator + (const Complex& c);
Complex operator - (const Complex& c);
Complex operator * (const Complex& c);
Complex operator / (const Complex& c);
bool operator == (const Complex& c);
bool operator != (const Complex& c);
Complex& operator = (const Complex& c);
};
#endif
//Complex.cpp
#include "Complex.h"
#include <math.h>
Complex::Complex(double a, double b)
{
this->a = a;
this->b = b;
}
double Complex::getA()
{
return a;
}
double Complex::getB()
{
return b;
}
double Complex::getModulus()
{
return sqrt(a * a + b * b);
}
Complex Complex::operator + (const Complex& c)
{
double na = a + c.a;
double nb = b + c.b;
Complex ret(na, nb);
return ret;
}
Complex Complex::operator - (const Complex& c)
{
double na = a - c.a;
double nb = b - c.b;
Complex ret(na, nb);
return ret;
}
Complex Complex::operator * (const Complex& c)
{
double na = a * c.a - b * c.b;
double nb = b * c.a + a * c.b;
Complex ret(na, nb);
return ret;
}
Complex Complex::operator / (const Complex& c)
{
double na = (a * c.a + b * c.b) / (c.a * c.a + c.b * c.b);
double nb = (b * c.a - a * c.b) / (c.a * c.a + c.b * c.b);
Complex ret(na, nb);
return ret;
}
bool Complex::operator == (const Complex& c)
{
return (a == c.a) && (b == c.b);
}
bool Complex::operator != (const Complex& c)
{
return !(*this == c);
}
Complex& Complex::operator = (const Complex& c)
{
if(this != &c)
{
a = c.a;
b = c.b;
}
return *this;
}
//test.cpp
#include <stdio.h>
#include <string.h>
#include "Complex.h"
int main()
{
Complex c1(1,2);
Complex c2(3,6);
Complex c3 = c2 - c1;
Complex c4 = c1 * c3;
Complex c5 = c2 / c1;
printf("c1.a = %f, c1.b = %f\n",c1.getA(),c1.getB());
printf("c2.a = %f, c2.b = %f\n",c2.getA(),c2.getB());
printf("c3.a = %f, c3.b = %f\n",c3.getA(),c3.getB());
printf("c4.a = %f, c4.b = %f\n",c4.getA(),c4.getB());
printf("c5.a = %f, c5.b = %f\n",c5.getA(),c5.getB());
Complex c6(2,4);
printf("c3 == c6:%d \n",c3 == c6);
(c3 = c2) = c1;
printf("c1.a = %f, c1.b = %f\n",c1.getA(),c1.getB());
printf("c2.a = %f, c2.b = %f\n",c2.getA(),c2.getB());
printf("c3.a = %f, c3.b = %f\n",c3.getA(),c3.getB());
return 0;
}
//编译运行
$ ./a.out
c1.a = 1.000000, c1.b = 2.000000
c2.a = 3.000000, c2.b = 6.000000
c3.a = 2.000000, c3.b = 4.000000
c4.a = -6.000000, c4.b = 8.000000
c5.a = 3.000000, c5.b = 0.000000
c3 == c6:1
c1.a = 1.000000, c1.b = 2.000000
c2.a = 3.000000, c2.b = 6.000000
c3.a = 1.000000, c3.b = 2.000000
4、注意事项
- C++规定赋值操作符(=)只能重载为成员函数
- 操作符重载不能改变原操作符的优先级
- 操作符重载不能改变操作数的个数
- 操作符重载不能改变操作符的原有语义