Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3], val = 3
Python 实现:
# -*- coding:utf-8 -*-
'''
Created on 2017年5月5日
@author: ZhuangLiang
'''
class Solution(object):
def removeElement(self, nums, val):
"""
:type nums: List[int]
:type val: int
:rtype: int
"""
lenth=len(nums)
i=0;
while i<lenth:
if nums[i]==val:
nums.remove(nums[i])
lenth=lenth-1
else:
i=i+1
return lenth
if __name__ == '__main__':
num=[1,1,1,2,2,3,5,5,7]
s=Solution()
print(s.removeElement(num,1))
for i in num:
print(i)
4704



被折叠的 条评论
为什么被折叠?



