LeetCode算法题——Palindrome Number

11-4 AEB 算法原理及系统组成 本专题旨在探讨如何利用仿真软件开发自动紧急制动系统AEB,主要通过整理开发流程,实现从需求到验证的全流程掌握,为后续开发提供支持;同时,研究了如何在汽车自动驾驶仿真工具中开发自己的算法,并解决了从ISO、E-CNAP、GB/T以及交通法规等提炼出功能需求的问题,以快速实现原型模型的开发。本专题重点讲解了AEB的工作原理、系统/软件架构和需求、算法模型及实现、CCRs/CCRb/CCRm建模与仿真、VRU-AEB-B/P/M建模与仿真,同时还提供了测试用例,期待将AEB算法成功地产品化。 阅读详情

Determine whether an integer is a palindrome. Do this without extra space.

click to show spoilers.

Some hints:

Could negative integers be palindromes? (ie, -1)

If you are thinking of converting the integer to string, note the restriction of using extra space.

You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?

There is a more generic way of solving this problem.

算法思想:
1 将整数转换成倒序的整数,然后比较两个数是否相等
2 提取头尾两个数,然后判断它们是否相等,判断后去掉头尾两个数

#include <iostream>
using namespace std;
class Solution {
public:
    bool isPalindrome(int x) {
        int y=x;
        if(y<0){
            return false;
        }
        int maxNum[10]={2,1,4,7,4,8,3,6,4,7};
        bool flag=false;
//        bool isNeg=false;
//        if(y<0){
//            y=-y;
//            isNeg=true;
//        }
        if(y/1000000000!=0){
            flag=true;
        }

        int s=0,j=0,m;
        while(y!=0){           
            m=y%10;
            if(flag){
                if(m>maxNum[j]){
                    return false;
                }else if(m<maxNum[j]){
                    flag=false;
                }
                j++;
            }
            y=y/10;
            s=s*10+m;
        }
//        if(isNeg){
//            s=-s;
//        }
        if(s==x){
            return true;
        }else{
            return false;
        }
//        return s;
    }
};

int main(){
    Solution sol;
    cout<<sol.isPalindrome(-2147447412)<<endl;
}
LSTM量化选股实战:从数据清洗到回测归因的工程化闭环 LSTM(长短期记忆网络)是一种专为建模长程依赖而设计的循环神经网络,其门控机制能有效应对金融时序数据的非线性、高噪声与动态演化特性。相比传统统计模型或简单RNN,LSTM在股价趋势建模中展现出更强的鲁棒性与泛化能力,尤其适合处理日频多因子时序信号。其技术价值不仅在于提升预测精度,更在于支撑可归因、可审计的量化策略工程实践——从特征构建、标签定义到滚动回测,每一步都需严防未来信息泄露与过拟合风险。典型应用场景包括A股多因子选股、行业轮动信号生成及Alpha组合优化。本文聚焦LSTM在真实量化场景中的落地难点 阅读详情

相关推荐

用Java实现森林冰火人游戏

g.drawString("游戏结束", CELL_SIZE * COLS / 2 - 100, CELL_SIZE * ROWS / 2);g.drawString("难度级别: " + difficultyLevel, 10, CELL_SIZE * ROWS + 60);g.drawString("生命值: " + playerHealth, 10, CELL_SIZE * ROWS + 20);setTitle("森林冰火人");

2401_82778412的博客 1734

LeetCode算法题之9:Palindrome Number

LeetCode之9:Palindrome Number 问题描述: 判断一个数字式否是回文数字,即判断它是否是对称的。原题地址 问题的陷阱与难点: 无 缺陷代码(79.35%) public boolean isPalindrome(int x) { if (x &lt; 0) { return false; } List&lt;Integer&gt; ...

veatheroe的博客 225

【Telephony】Telephony总纲!Phone进程流程(AOSP)

整个Framework层的Telephony框架运行在一个叫做Phone(com.android.phone)的进程中。 Phone进程启动的过程中,会初始化非常多的分支功能,SIM卡流程初始化就是其中之一,所以我觉得有必要写一下Phone进程的框架

weixin_44513784的博客 1975

LeetCode算法题之Palindrome Number

问题描述: Determine whether an integer is a palindrome. Do this without extra space. 判断一个int型数据是不是回文数,保证计算空间不会溢出 解题思路: 转为字符串,进行前后比较 class Solution { public: bool isPalindrome(int x) { if(res

LovePeppa的专栏 598

基于DE2-115红外解码实验

基于DE2-115红外解码实验   一、   功能描述 在同一个遥控电路中通常要使用实现不同的遥控功能或区分不同的机器类型, 这样就要求信号按一定的编码传送,编码则会由编码芯片或电路完成。对应于编码芯片通常会有相配对的解码芯片或包含解码模块的应用芯片。在实际的产品设计或业余电子制作中,编码芯片并一定能完成我们要求的功能,这时我们就需要了解所使用的编码芯片到底是如何编码的。只有知道编码方式,我...

乘风的博客 2515

CSP-J第一道模拟题——贪心的小朋友

第一行是一个整数 n,表示糖果的堆数 第二行是由空格分隔的 n 个正整数,即数组 candies,表示每堆糖果的数量。后一个离场的小朋友所拿的糖果总堆数必须小于前一个小朋友(对第一个小朋友没有限制)后一个离场的小朋友所拿的糖果总量必须小于前一个小朋友(对第一个小朋友没有限制)这道题目很简单,但是必须删去无用的部分,看清题目,才能得分哦!输出一行共一个整数,表示最多可能有多少个小朋友吃上了美味的糖果。输出最多可能有多少个小朋友吃上了美味的糖果。离场之后的小朋友才能吃上美味的糖果。每个小朋友可以拿多堆糖果。

weixin_29959235的博客 639

【算法】LeetCode算法题-Palindrome Number

这是悦乐书的第144次更新,第146篇原创 今天这道题和回文有关,即从前往后和从后往前是一样的,如“上海自来水来自海上”就是一个回文字符串,如整数121就是回文数,这些都是和回文相关的。 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第3题(顺位题号是9),给定一个整数,判断其是否为回文整数,即向前读和向后读的整数一样。 输入: 121 输出: true 输入: -12...

小川的博客 345

ffmpeg在windows的安装、合并、切片、.m4s、.m3u8处理

自己处理视频,我用的工具是 ffmpeg,因为涉及到.m3u8格式和.m4s格式的一些操作。ffmpeg的介绍我就不多说了,这里是它的官网地址: https://ffmpeg.org/ ,这里是文档: https://ffmpeg.org/documentation.html (看的头大,没咋看下去)...

一只爱吃糖的小羊 2689

用Python3实现LeetCode算法题系列——No.009 Palindrome Number [Easy]

目录 1. 题目 2. 提交的代码 3. 运行效果 4. 完整代码 1. 题目 Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 ...

阿耀的博客 532

基因家族Motif 分析

MEME

hgz2020的博客 6317

ANSYS Workbench对称分析进阶:手把手教你用Pre-Meshed Cyclic Region处理外部导入的复杂网格模型

本文详细介绍了ANSYS Workbench中Pre-Meshed Cyclic Region功能在处理外部导入复杂网格模型时的应用。通过循环对称分析技术,可显著减少计算资源消耗,特别适用于叶轮机械、齿轮组等周期性结构分析。文章深入解析了该功能的底层逻辑,并提供了从NASTRAN文件导入的离心压缩机叶轮案例,帮助工程师克服网格匹配难题。

weixin_28630185的博客 313

LeetCode OJ算法题(九):Palindrome Number

题目: Determine whether an integer is a palindrome. Do this without extra space. 解法: 题目很简短,

op_yu的专栏 459

YOLO26训练教程,训练自己的数据集教学,从源码下载,配置虚拟环境,准备数据集、训练、验证、推理测试 。实现0到1的完整教学过程。快速入门必看

本文详细介绍了YOLO26目标检测模型的配置与使用流程:1)下载YOLOv11源码并创建Python3.10虚拟环境;2)安装PyTorch2.5.1及相关依赖库;3)准备数据集并修改配置文件;4)编写训练脚本设置参数(640x640分辨率、500轮次);5)验证模型效果;6)使用训练好的模型进行推理测试;7)生成可视化热力图。整个过程涵盖了从环境搭建到模型应用的全流程,并提供了清华镜像源加速下载。

Ai缝合怪、助力小伙伴高效发论文 5285

python写算法题:leetcode: 9. Palindrome Number

class Solution(object): def isPalindrome(self, x): """ :type x: int :rtype: bool """ if x<0: return False base=1 while x>=base*10:

649

深度学习工具包 DeepLearningToolbox

深度学习工具包Deprecation notice.-----This toolbox is outdated and no longer maintained.There are much better tools available for deep learning than this toolbox, e.g. [Theano](http://deeplearning.net/software/theano/), [torch](http://torch.ch/) or [tensorflow](http://www.tensorflow.org/)I would suggest you use one of the tools mentioned above rather than use this toolbox.Best, Rasmus.DeepLearnToolbox================A Matlab toolbox for Deep Learning.Deep Learning is a new subfield of machine learning that focuses on learning deep hierarchical models of data.It is inspired by the human brain's apparent deep (layered, hierarchical) architecture.A good overview of the theory of Deep Learning theory is[Learning Deep Architectures for AI](http://www.iro.umontreal.ca/~bengioy/papers/ftml_book.pdf)For a more informal introduction, see the following videos by Geoffrey Hinton and Andrew Ng.* [The Next Generation of Neural Networks](http://www.youtube.com/watch?v=AyzOUbkUf3M) (Hinton, 2007)* [Recent Developments in Deep Learning](http://www.youtube.com/watch?v=VdIURAu1-aU) (Hinton, 2010)* [Unsupervised Feature Learning and Deep Learning](http://www.youtube.com/watch?v=ZmNOAtZIgIk) (Ng, 2011)If you use this toolbox in your research please cite [Prediction as a candidate for learning deep hierarchical models of data](http://www2.imm.dtu.dk/pubdb/views/publication_details.php?id=6284)```@MASTERSTHESIS\{IMM2012-06284, author = "R. B. Palm", title = "Prediction as a candidate for learning deep hierarchical models of data", year = "2012",}```Contact: rasmusbergpalm at gmail dot comDirectories included in the toolbox-----------------------------------`NN/` - A library for Feedforward Backpropagation Neural Networks`CNN/` - A library for Convolutional Neural Networks`DBN/` - A library for Deep Belief Networks`SAE/` - A library for Stacked Auto-Encoders`CAE/` - A library for Convolutional Auto-Encoders`util/` - Utility functions used by the libraries`data/` - Data used by the examples`tests/` - unit tests to verify toolbox is workingFor references on each library check REFS.mdSetup-----1. Download.2. addpath(genpath('DeepLearnToolbox'));Example: Deep Belief Network---------------------```matlabfunction test_example_DBNload mnist_uint8;train_x = double(train_x) / 255;test_x = double(test_x) / 255;train_y = double(train_y);test_y = double(test_y);%% ex1 train a 100 hidden unit RBM and visualize its weightsrand('state',0)dbn.sizes = [100];opts.numepochs = 1;opts.batchsize = 100;opts.momentum = 0;opts.alpha = 1;dbn = dbnsetup(dbn, train_x, opts);dbn = dbntrain(dbn, train_x, opts);figure; visualize(dbn.rbm{1}.W'); % Visualize the RBM weights%% ex2 train a 100-100 hidden unit DBN and use its weights to initialize a NNrand('state',0)%train dbndbn.sizes = [100 100];opts.numepochs = 1;opts.batchsize = 100;opts.momentum = 0;opts.alpha = 1;dbn = dbnsetup(dbn, train_x, opts);dbn = dbntrain(dbn, train_x, opts);%unfold dbn to nnnn = dbnunfoldtonn(dbn, 10);nn.activation_function = 'sigm';%train nnopts.numepochs = 1;opts.batchsize = 100;nn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.10, 'Too big error');```Example: Stacked Auto-Encoders---------------------```matlabfunction test_example_SAEload mnist_uint8;train_x = double(train_x)/255;test_x = double(test_x)/255;train_y = double(train_y);test_y = double(test_y);%% ex1 train a 100 hidden unit SDAE and use it to initialize a FFNN% Setup and train a stacked denoising autoencoder (SDAE)rand('state',0)sae = saesetup([784 100]);sae.ae{1}.activation_function = 'sigm';sae.ae{1}.learningRate = 1;sae.ae{1}.inputZeroMaskedFraction = 0.5;opts.numepochs = 1;opts.batchsize = 100;sae = saetrain(sae, train_x, opts);visualize(sae.ae{1}.W{1}(:,2:end)')% Use the SDAE to initialize a FFNNnn = nnsetup([784 100 10]);nn.activation_function = 'sigm';nn.learningRate = 1;nn.W{1} = sae.ae{1}.W{1};% Train the FFNNopts.numepochs = 1;opts.batchsize = 100;nn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.16, 'Too big error');```Example: Convolutional Neural Nets---------------------```matlabfunction test_example_CNNload mnist_uint8;train_x = double(reshape(train_x',28,28,60000))/255;test_x = double(reshape(test_x',28,28,10000))/255;train_y = double(train_y');test_y = double(test_y');%% ex1 Train a 6c-2s-12c-2s Convolutional neural network %will run 1 epoch in about 200 second and get around 11% error. %With 100 epochs you'll get around 1.2% errorrand('state',0)cnn.layers = { struct('type', 'i') %input layer struct('type', 'c', 'outputmaps', 6, 'kernelsize', 5) %convolution layer struct('type', 's', 'scale', 2) %sub sampling layer struct('type', 'c', 'outputmaps', 12, 'kernelsize', 5) %convolution layer struct('type', 's', 'scale', 2) %subsampling layer};cnn = cnnsetup(cnn, train_x, train_y);opts.alpha = 1;opts.batchsize = 50;opts.numepochs = 1;cnn = cnntrain(cnn, train_x, train_y, opts);[er, bad] = cnntest(cnn, test_x, test_y);%plot mean squared errorfigure; plot(cnn.rL);assert(er<0.12, 'Too big error');```Example: Neural Networks---------------------```matlabfunction test_example_NNload mnist_uint8;train_x = double(train_x) / 255;test_x = double(test_x) / 255;train_y = double(train_y);test_y = double(test_y);% normalize[train_x, mu, sigma] = zscore(train_x);test_x = normalize(test_x, mu, sigma);%% ex1 vanilla neural netrand('state',0)nn = nnsetup([784 100 10]);opts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samples[nn, L] = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.08, 'Too big error');%% ex2 neural net with L2 weight decayrand('state',0)nn = nnsetup([784 100 10]);nn.weightPenaltyL2 = 1e-4; % L2 weight decayopts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samplesnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex3 neural net with dropoutrand('state',0)nn = nnsetup([784 100 10]);nn.dropoutFraction = 0.5; % Dropout fraction opts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samplesnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex4 neural net with sigmoid activation functionrand('state',0)nn = nnsetup([784 100 10]);nn.activation_function = 'sigm'; % Sigmoid activation functionnn.learningRate = 1; % Sigm require a lower learning rateopts.numepochs = 1; % Number of full sweeps through dataopts.batchsize = 100; % Take a mean gradient step over this many samplesnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex5 plotting functionalityrand('state',0)nn = nnsetup([784 20 10]);opts.numepochs = 5; % Number of full sweeps through datann.output = 'softmax'; % use softmax outputopts.batchsize = 1000; % Take a mean gradient step over this many samplesopts.plot = 1; % enable plottingnn = nntrain(nn, train_x, train_y, opts);[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');%% ex6 neural net with sigmoid activation and plotting of validation and training error% split training data into training and validation datavx = train_x(1:10000,:);tx = train_x(10001:end,:);vy = train_y(1:10000,:);ty = train_y(10001:end,:);rand('state',0)nn = nnsetup([784 20 10]); nn.output = 'softmax'; % use softmax outputopts.numepochs = 5; % Number of full sweeps through dataopts.batchsize = 1000; % Take a mean gradient step over this many samplesopts.plot = 1; % enable plottingnn = nntrain(nn, tx, ty, opts, vx, vy); % nntrain takes validation set as last two arguments (optionally)[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');```[![Bitdeli Badge](https://d2weczhvl823v0.cloudfront.net/rasmusbergpalm/deeplearntoolbox/trend.png)](https://bitdeli.com/free "Bitdeli Badge")

OV9734 DATASHEET,完整规格书

OV9734完整规格书,包括电气参数,尺寸规格,寄存器配置表等

leetcode:Palindrome Number (判断数字是否回文串) 【面试算法题】

Determine whether an integer is a palindrome. Do this without extra space. 题意判断数字是否是回文串,只能用常数空间,不能转换成字符串,不能反转数字。

Havenoidea 的专栏 1万+

win10 跳过U8环境检测的IE WebControls.rar

win10 安装u8的时候 提示IE WebControls 不通过,这个工具可以欺骗u8的检查。 跳过U8环境检测的IE WebControls。提示导入失败后,重新检测通过。

【仅用于个人整理记忆】LeetCode算法题之9. Palindrome Number(easy)

声明: 如标题所示,因本人为AI路上的新手,文章仅用于辅助个人的整理记忆,理解难免有偏差之处,都是个人拙见,如给其他同僚造成困扰,还请见谅,非常非常非常欢迎私信共同讨论,共同进步 题目描述: Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward...

DaMoWangZQ的博客 190

TMS_WebGMaps_1.9.8.0_Full_Source

TMS_WebGMaps_1.9.8.0_Full_Source 全源码 delphi cbuilder

【力扣Leetcode题解系列之0009—Palindrome Number 回文数:深入剖析与拓展】

摘要: 本文详细解析了力扣第9题「回文数」的两种解法:字符串转换法和数字翻转法。字符串法通过比较字符判断回文,时间复杂度O(log₁₀n),空间复杂度O(log₁₀n);数字翻转法通过数学运算反转数字,空间优化至O(1)。文章还提供了Python/Java/C/C++/Go多语言实现,并拓展了判断任意进制回文数的问题,建议处理负数、进制转换和字符比较。两种解法中翻转数字法更优,尤其适合限制空间的情况。

youngerwang的博客 718

Leetcode 3646. Next Special Palindrome Number

Leetcode 3646. Next Special Palindrome Number

codename_cys的博客 818

leetcode 9 Palindrome Number

题目描述: https://leetcode.com/problems/palindrome-number/ AC代码: class Solution { public: bool isPalindrome(int x) { int t=0; //如果x为负数、不等于零但只有一位,直接返回false if(x < 0 || x ...

Forlogenの解忧杂货铺 314

leetcode09-Palindrome Number之Java版本

我的leetcode之旅,该篇章主要完成使用Java实现算法。这是第9篇Palindrome Number

peace唠叨 1410

闯关leetcode——9. Palindrome Number

leetcode第9题

方亮的专栏 2297

leetcode - 0009. Palindrome Number

leetcode - 0009. Palindrome Number 题目大意 判断一个整数是否是回文数。回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数。 解题思路 判断一个整数是不是回文数。 简单题。注意会有负数的情况,负数,个位数,10 都不是回文数。其他的整数再按照回文的规则判断。 #include <stdio.h> #define INT_MIN (-2147483647 - 1) #define INT_MAX 2147483647 class S

虾球 176

LeetCode 9. Palindrome Number (Java版; Easy)

welcome to my blog LeetCode Top Interview Questions 9. Palindrome Number (Java版; Easy) 题目描述 Determine whether an integer is a palindrome. An integer is a palindrome when it reads t...

littlehaes的博客 337

LeetCode Palindrome Partitioning II

将一个字符串分割成若干个子字符串,使得子字符串都是回文字符串,要求最少需要几次分割能够满足需求。

DRFish 4015

Palindrome Number

LeetCode原题:Palindrome Number Determine whether an integer is a palindrome. Do this without extra space. Spoilers: Could negative integers be palindromes? (ie, -1) If you are thinking of conver

qq_34252666的博客 210
上一篇: LeetCode算法题——String to Integer (atoi)
下一篇: Python面向对象编程(5)——类的特殊方法
LZTree
博客等级 码龄12年 2粉丝 34原创
评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

个

红包个数最小为10个

元

红包金额最低5元

当前余额3.43元 前往充值 >
需支付:10.00元
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付元
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值